Answer:
Step-by-step explanation:
Hello There!
Once again we are going to use trigonometry to solve for x
Here are the <u>Trigonometric Ratios</u>
sin = opposite divided by hypotenuse
cos = adjacent divided by hypotenuse
tan = opposite divided by adjacent
we need to find x and we are given its opposite side length (58) and the adjacent side length (19)
this corresponds with tangent so once again we will be using tangent to solve for x
Looking at tangent we see that its equal to opposite divided by adjacent so we create an equation
now we have
Once again we need to get rid of the tan
to do so we take the inverse of tan ( tan^-1) and apply it to each side
finally we round to the nearest tenth
we're left with x = 71.9
By using y=mx+b you get y=-3/8x-17/8
The perimeter is 1/2 the perimeter of ABCD because the scale factor is 1/2. It would be 10 units.
1/3 ln(<em>x</em>) + ln(2) - ln(3) = 3
Recall that 
, so
ln(<em>x</em> ¹ʹ³) + ln(2) - ln(3) = 3
Condense the left side by using sum and difference properties of logarithms:
Then
ln(2/3 <em>x</em> ¹ʹ³) = 3
Take the exponential of both sides; that is, write both sides as powers of the constant <em>e</em>. (I'm using exp(<em>x</em>) = <em>e</em> ˣ so I can write it all in one line.)
exp(ln(2/3 <em>x</em> ¹ʹ³)) = exp(3)
Now exp(ln(<em>x</em>)) = <em>x </em>for all <em>x</em>, so this simplifies to
2/3 <em>x</em> ¹ʹ³ = exp(3)
Now solve for <em>x</em>. Multiply both sides by 3/2 :
3/2 × 2/3 <em>x</em> ¹ʹ³ = 3/2 exp(3)
<em>x</em> ¹ʹ³ = 3/2 exp(3)
Raise both sides to the power of 3:
(<em>x</em> ¹ʹ³)³ = (3/2 exp(3))³
<em>x</em> = 3³/2³ exp(3×3)
<em>x</em> = 27/8 exp(9)
which is the same as
<em>x</em> = 27/8 <em>e</em> ⁹
22 I think If I worked it out right
