Question

Brad puts an equal amount of money in his savings account once a month.He started with $27.The next month he had $44 in his account.Two months after that he had $78 in his account.How much money will brad havr in his account after 6 months?

Answer 1

Answer:

$129

Step-by-step explanation:

$44-$27=$17 per month

$17 times 3=$51

$78 plus $51= $129 after 6 months

Answer 2

Answer: brad will have $112 in his account after 6 months.

Step-by-step explanation:

Since he puts equal amount of money in his savings account once a month, the rate at which the money is increasing is in arithmetic progression. The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = $27

d = 44 - 27 = 17

n = 6 months

We want to determine the value of the 6th term, T6. Therefore,

T6 = 27 + (6 - 1)17

T6 = 27 + 85

T6 = $112