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Hoochie [10]
3 years ago
14

Which point is a solution to the linear inequality y < x + 2?

Mathematics
2 answers:
jekas [21]3 years ago
7 0
First you can try substituting (0,0) to see if that works because it is the easiest.

0<0+2
0<2

That is true so (0,0) is solution of y
Charra [1.4K]3 years ago
7 0

Answer:

Step-by-step explanation:

When we are looking for a solution of inequality , there are various possibilities. We can have no solution to it or a finite solution of many/infinite solutions . Lets try to figure out one point that is asked to find for this inequality .

The inequality we are dealing with is y < x+2

Since , y= x+2 is an equation of line , it means the given inequality will represent one side of the line on a cartesian axis .

The very basic and easiest point we use to find the solution is (0,0) also known as the origin test . so lets try to figure out if the point (0,0) is a solution or not .

To find if (0,0) is a solution or not we need to plug it in the given inequality and check if it holds true . so when we plug (0,0) we get

0 <0 +2

0< 2

Which is true so we can say that (0,0) is a point which is solution of the given inequality .

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I've included two questions. Hopefully you can help me with both. Thanks!
lubasha [3.4K]

Answer:

  1.  value is 0; x-3 is a factor . . . . . . . . . . . . . .third choice

  2.  evaluates at x = -1; remainder is -11 . . . . first choice

Step-by-step explanation:

Dividing f(x) by (x -a) gives ...

  f(x)/(x -a) = g(x) +r/(x -a) . . . . some quotient and a remainder r

If we multiply this expression by (x -a), we see ...

  f(x) = (x -a)g(x) +r

so

  f(a) = (a -a)g(a) +r . . . . . evaluate the above equation at x=a

  f(a) = 0 +r

  f(a) = r . . . . . . . . . a statement of the remainder theorem

If r=0, then x-a is a factor of f(x) = (x-a)g(x).

___

1. We have "a" = 3, and f(3) = 0. Therefore (x-3) is a factor.

__

2. We have "a" = -1, and f(-1) = -11. Therefore the remainder from division by (x+1) is -11.

6 0
4 years ago
Which function is negative for the interval [–1, 1]? On a coordinate plane, a curved line with a minimum value of (negative 1, n
Doss [256]

Answer:

A. On a coordinate plane, a curved line with a minimum value of (negative 1, negative 2), crosses the x-axis at (negative 2.5, 0) and (0.5, 0), and the y-axis at (0, negative 1).

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

A. On a coordinate plane, a curved line with a minimum value of (negative 1, negative 2), crosses the x-axis at (negative 2.5, 0) and (0.5, 0), and the y-axis at (0, negative 1).

B. On a coordinate plane, a curved line with a minimum value of (0, negative 2), crosses the x-axis at (negative 1.5, 0) and (1.5, 0).

C.  On a coordinate plane, a curved line with a maximum value of (0, 2) and a minimum value of (1.5, negative 2.75), crosses the x-axis at (negative 0.6, 0) and (0.6, 0).

D. On a coordinate plane, a curved line with a maximum value of (negative 1.25, 4) and a minimum value of (1.5, negative 3.5), crosses the x-axis at (negative 1.75, 0), (0.75, 0), and (1.75, 0), and crosses the y-axis at (0, 2).

Apologies if I am wrong, I am not great with graphs but I hoped I helped.

<3 Enjoy,

    Dea

7 0
3 years ago
Read 2 more answers
Estimate using a rate per 100 of 74% of 315. 89% of 195
LiRa [457]
<span><span>1.       </span>Given numbers:
74 % of 315
89% of 195

now, let’s solve the first given numbers:
=> 74% of 315
=> 315 is the 100%
Let’s convert 74% into decimals
=> 74% = .74
=> 315 * .74 = 233.1, the value of 74% of 315
Let’s solve the second given:
=> 89% of 195
where 195 is the 100%
=> 89% = .89
=> 195 * .89
=> 173.55, the value of 89% of 195</span>



3 0
4 years ago
3 and 3/8 tons equals how many pounds
Tamiku [17]
The answer is 6750 pounds
8 0
3 years ago
A bank offers simple interest loans at an interest rate of 6% per year. How much interest will you pay if you borrow.$1,200 for
kenny6666 [7]

Answer:

$216

Step-by-step explanation:

6% of 1200 = 72

72x3=216

7 0
3 years ago
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