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Hoochie [10]
3 years ago
14

Which point is a solution to the linear inequality y < x + 2?

Mathematics
2 answers:
jekas [21]3 years ago
7 0
First you can try substituting (0,0) to see if that works because it is the easiest.

0<0+2
0<2

That is true so (0,0) is solution of y
Charra [1.4K]3 years ago
7 0

Answer:

Step-by-step explanation:

When we are looking for a solution of inequality , there are various possibilities. We can have no solution to it or a finite solution of many/infinite solutions . Lets try to figure out one point that is asked to find for this inequality .

The inequality we are dealing with is y < x+2

Since , y= x+2 is an equation of line , it means the given inequality will represent one side of the line on a cartesian axis .

The very basic and easiest point we use to find the solution is (0,0) also known as the origin test . so lets try to figure out if the point (0,0) is a solution or not .

To find if (0,0) is a solution or not we need to plug it in the given inequality and check if it holds true . so when we plug (0,0) we get

0 <0 +2

0< 2

Which is true so we can say that (0,0) is a point which is solution of the given inequality .

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The equation 9cos(sin¯¹(x)) = √(81 – 81x²) is true since L.H.S = R.H.S

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<h3>What is an equation?</h3>

An equation is a mathematical expression that show the relationship between two variables.

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So, L.H.S = 9cos(sin¯¹(x))

= 9[√{1 - sin²(sin¯¹(x)}] (Since sin²y + cos²y = 1 ⇒ cosy = √[1 - sin²y])

9[√{1 - sin²(sin¯¹(x)}] = √9² × √{1 - sin²(sin¯¹(x)}]

= √[9² × {1 - sin²(sin¯¹(x)}]

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= √(81 – 81x²)

= R.H.S

So, the equation 9cos(sin¯¹(x)) = √(81 – 81x²) is true since L.H.S = R.H.S

Learn more about equations here:

brainly.com/question/2888445

#SPJ1

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