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Hoochie [10]
2 years ago
14

Which point is a solution to the linear inequality y < x + 2?

Mathematics
2 answers:
jekas [21]2 years ago
7 0
First you can try substituting (0,0) to see if that works because it is the easiest.

0<0+2
0<2

That is true so (0,0) is solution of y
Charra [1.4K]2 years ago
7 0

Answer:

Step-by-step explanation:

When we are looking for a solution of inequality , there are various possibilities. We can have no solution to it or a finite solution of many/infinite solutions . Lets try to figure out one point that is asked to find for this inequality .

The inequality we are dealing with is y < x+2

Since , y= x+2 is an equation of line , it means the given inequality will represent one side of the line on a cartesian axis .

The very basic and easiest point we use to find the solution is (0,0) also known as the origin test . so lets try to figure out if the point (0,0) is a solution or not .

To find if (0,0) is a solution or not we need to plug it in the given inequality and check if it holds true . so when we plug (0,0) we get

0 <0 +2

0< 2

Which is true so we can say that (0,0) is a point which is solution of the given inequality .

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Answer: what is ∠ ?

Step-by-step explanation:

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3 years ago
Solve the in quality x plus 1&lt;7
RUDIKE [14]

Answer:

x<6

Step-by-step explanation:

x+1 < 7

Subtract 1 from each side

x+1-1<7-1

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7 0
3 years ago
X-y=5 and x^2y=5x+6​
sergeinik [125]

By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.

<h3>How to solve a system of equations</h3>

In this question we have a system formed by a <em>linear</em> equation and a <em>non-linear</em> equation, both with no <em>trascendent</em> elements and whose solution can be found easily by algebraic handling:

x - y = 5      (1)

x² · y = 5 · x + 6       (2)

By (1):

y = x + 5

By substituting on (2):

x² · (x + 5) = 5 · x + 6

x³ + 5 · x² - 5 · x - 6 = 0

(x + 5.693) · (x - 1.430) · (x + 0.737) = 0

There are three solutions: x₁ ≈ 5.693, x₂ ≈ 1.430, x₃ ≈ - 0.737

And the y-values are found by evaluating on (1):

y = x + 5

x₁ ≈ 5.693

y₁ ≈ 10.693

x₂ ≈ 1.430

y₂ ≈ 6.430

x₃ ≈ - 0.737

y₃ ≈ 4.263

By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.

To learn more on nonlinear equations: brainly.com/question/20242917

#SPJ1

8 0
1 year ago
A rectangular filed is 190m by 270m . A rectangular barn is 23 m by 40 m is built in the field .
Anika [276]

Answer: 50,380m

Step-by-step explanation:

190m * 270m = 51,300m

23m * 40m = 920m

Because the barn is in the field, we subtract the barn's area from the field's area, which leaves us with

51,300m - 920m = 50,380m

4 0
3 years ago
HELP PLEASE DUE IN 3 MINUTES
Furkat [3]
Hurry the answer is 6
8 0
2 years ago
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