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Kobotan [32]
3 years ago
13

What is -14-7-(-25) equal? Please tell me lol

Mathematics
2 answers:
Gemiola [76]3 years ago
4 0
Your ANSWER is
4

I really hope this helps let me know if you need a step by step
Elza [17]3 years ago
4 0
-14-7 is -21–25= 4
The answer is 5
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which point could be removed in order to make it the relation a function? (-4, 3) (-5, 6) (1, 0) (-4, 5) (9, 5) (0, -7)
svetoff [14.1K]

In a function, each input (x-) value has exactly one output (y-) value. That's not the case here, where we have (-4,5) and (-4,3) (two different y-values for one x-value). Eliminating either (-4,5) or (-4,3) will make this relation into a function.

6 0
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What is the graph for the equation
aev [14]

Answer:78.909899

Step-by-step explanation:

90.09

5 0
4 years ago
Solve the following by elimination method <br> 11x+15y+23=0 and 7x-2y-20=0
mr Goodwill [35]
Let 11x + 15y + 23 = 0 be equation (1)
And 7x - 2y - 20 = 0 be equation (2)

Multiply equation (1) by 2:
22x + 30y + 46 = 0

Multiply equation (2) by 15:
105x - 30y - 300 = 0

Add equations (1) and (2):
22x + 105x + 30y - 30y + 46 - 300 = 0
127x - 254 = 0
127x = 254
x = 254/127
[x = 2]

Substitute x = 2 in equation (1) to find y:
11(2) + 15y + 23 = 0
22 + 15y + 23 = 0
15y + 45 = 0
15y = -45
y = -45/15
y = -3

Therefore, x = 2 and y = -3.
7 0
4 years ago
Which of the given side lengths form a right triangle?
vlada-n [284]
15 in 12 in 9 in


15 squared ( the hypotenuse) equals 225 and 12 squared plus 9 squared equals 225 as well. Since they equal each other they are a right triangle
3 0
4 years ago
Find the perimeter of quadrilateral ABCD with vertices A(-2,-2), B(-1,3),
drek231 [11]

Answer:

<h2> 22.2</h2>

Step-by-step explanation:

Step one

given the coordinates

ABCD with vertices A(-2,-2), B(-1,3), C(5, 3), and D(4, -2)

AB=(-2,-2),(-1,3)

BC=(-1,3), (5, 3)

CD=(5, 3),(4, -2)

DA=(4, -2),(-2,-2)

The distance between points AB=

AB= \sqrt (x_2-x_1)^2+(y_2-y_1)^2

AB= \sqrt (-1+2)^2+(3+2)^2\\\\AB= \sqrt 1^2+(5)^2\\\\AB= \sqrt26\\\\AB=5.1

The distance between points BC=

BC= \sqrt (5+1)^2+(3-3)^2\\\\BC= \sqrt 6^2+(0)^2\\\\BC= \sqrt36\\\\BC=6

The distance between points CD

CD= \sqrt (4-5)^2+(-2-3)^2\\\\CD= \sqrt -1^2+(-5)^2\\\\CD= \sqrt26\\\\CD=5.1

The distance between points DA

DA= \sqrt (4+2)^2+(-2+2)^2\\\\DA= \sqrt 6^2+(0)^2\\\\DA= \sqrt36\\\\DA=6

Hence the perimeter = 5.1+6+5.1+6

= 22.2

5 0
3 years ago
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