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Makovka662 [10]
3 years ago
9

someone please help

Mathematics
1 answer:
Savatey [412]3 years ago
4 0
Check the picture below.

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Prove that x+1 is a factor of x^n+1 where n is an odd positive integer.​
egoroff_w [7]

Answer:

because x^n+1 =

the number which is n and n is an odd number and my odd number is 3 so

x^3+1= 4

= x^4

7 0
3 years ago
There are 3 answers need help to get my grade up to a 70%
svetoff [14.1K]

Answer:

From (2, 1) move up one and over four

3 0
2 years ago
Shawna reduced the size of a rectangle to a height of 2 inches. What is the new width if it was originally 24 inches wide and 12
AfilCa [17]

Answer:

Step-by-step explanation:

Original Ratio              =                  New Ratio        All these problems are done the same way. Try to conquer the language.

The original ratio = 24 inches wide / 12 inches tall

Shawna's new ratio = you don't know / 2 inches in height (or tall)

Call what you don't know = x

24/12 = x / 2                        Cross multiply

12 * x = 24 * 2                     Combine the right

12 * x = 48                           Divide by 12

12x/12 = 48/12

x = 4

So the new height is 4 inches.  

5 0
2 years ago
One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p
scZoUnD [109]

Answer:

c^2 = 9dp

Step-by-step explanation:

Given

dx^2 + cx + p = 0

Let the roots be \alpha and \beta

So:

\alpha = 2\beta

Required

Determine the relationship between d, c and p

dx^2 + cx + p = 0

Divide through by d

\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0

x^2 + \frac{c}{d}x + \frac{p}{d} = 0

A quadratic equation has the form:

x^2 - (\alpha + \beta)x + \alpha \beta = 0

So:

x^2 - (2\beta+ \beta)x + \beta*\beta = 0

x^2 - (3\beta)x + \beta^2 = 0

So, we have:

\frac{c}{d} = -3\beta -- (1)

and

\frac{p}{d} = \beta^2 -- (2)

Make \beta the subject in (1)

\frac{c}{d} = -3\beta

\beta = -\frac{c}{3d}

Substitute \beta = -\frac{c}{3d} in (2)

\frac{p}{d} = (-\frac{c}{3d})^2

\frac{p}{d} = \frac{c^2}{9d^2}

Multiply both sides by d

d * \frac{p}{d} = \frac{c^2}{9d^2}*d

p = \frac{c^2}{9d}

Cross Multiply

9dp = c^2

or

c^2 = 9dp

Hence, the relationship between d, c and p is: c^2 = 9dp

8 0
3 years ago
Simplify 3x+(4x-3) <br><br> Pls :)
OLga [1]

Answer:

7x - 3

Step-by-step explanation:

3x+(4x-3)

Remove parenthesis

3x + 4x - 3

Combine like terms

3x + 4x = 7x

7x - 3

5 0
3 years ago
Read 2 more answers
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