D so 24
I hope this helps :)
Good luck
The slope would be 2/7 in order for any line to be parallel to it.
Check if there is a giggle throughout the full equation, since there isn’t, we group the equation and we get
(4ax-10bx)+(6ay-15by)
Factor out the gcf of the two groups
2x(2a-5b)+3y(2a-5b)
Not sure how to explain this step in words but so do this
(2x+3y)(2a-5b)
The solution is (2x+3y)(2a-5b)
