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2 years ago

Is 6/3*6=18 true or false?

Mathematics

2 answers:

gladu [14]2 years ago

8 0

Answer:

false

Step-by-step explanation:

6/3 is 2 and that times 6 is 12 not 18

Hitman42 [59]2 years ago

7 0

Answer:

nope its 12 g

Step-by-step explanation:

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2 years ago

Choose the expanded form of this expression 4(1/4 a + b - 6)

zalisa [80]

Answer:

a+4b-24

Step-by-step explanation:

4(1/4a+b−6)

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2 years ago

Estimate 76.216+66.36 by first rounding each number to the nearest whole number.

xeze [42]

Answer:

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Step-by-step explanation:

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2 years ago

$44 in 4 days or $____ per day

velikii [3]

Answer:

$11/ day

Step-by-step explanation:

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5 0

3 years ago

Read 2 more answers

The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co

Alona [7]

Answer:

95% Confidence interval for the variance:

$3.6511\leq \sigma^2\leq 34.5972$

95% Confidence interval for the standard deviation:

$1.9108\leq \sigma \leq 5.8819$

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

$s^2=2.89^2=8.3521$

The confidence interval for the variance is:

$\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}$

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

$\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128$

Then, the confidence interval can be calculated as:

$\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972$

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

$\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819$

6 0

3 years ago

Is 6/3*6=18 true or false?​

Is 6/3*6=18 true or false?