Answer:
10 9 8 7
Step-by-step explanation:
There are 10 choices for the first digit,
9 choices for the second digit,
8 choices for the third digit, and
7 choices for the fourth digit.
Using the fundamental counting principle, how many access codes are possible? 5,040
If the digits 0 through 9 could be repeated, how many access codes would be possible? 10,000
D. the length is the same as the length of MN
2,586,203 = 2,000,000 + 500,000 + 80,000 + 6,000 + 200 + 3
The answer to this is 5-3a
The answer is: 312 (Squared)
Step-by-step explanation:
(2×6 is 12. 12×2 is 24. Top and Bottom)
(12×6 is 72. 72×4 is 288. Both sides+Front and back)
(Adding those up would be: 288+24 = 312)