Question

Inverse Function In Exercise,analytically show that the functions are inverse functions.Then use the graphing utility to show this graphically.
f(x) = e^x - 1
g(x) = In(x + 1)

Answer 1

Step-by-step explanation:

We need to show whether

$f^{-1}(x) = g(x)$

or

$g^{-1}(x) = f(x)$

so we'll do either one of them,

we'll convert f(x) to f^-1(x) and lets see if it looks like g(x).

$f(x) = e^x - 1$

we can also write it as:

$y = e^x - 1$

now all we have to do is to make x the subject of the equation.

$y+1 = e^x$

$\ln{(y+1)} = x$

$x=\ln{(y+1)}$

now we'll interchange the variables

$y=\ln{(x+1)}$

this is the inverse of f(x)

$f^{-1}(x)=\ln{(x+1)}$

and it does equal to g(x)

$g(x)=\ln{(x+1)}$

Hence, both functions are inverse of each other!

This can be shown graphically too:

we can see that both functions are reflections of each other about the line y=x.