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3 years ago

12

There are some caps in a box. 1/6 of them are red, 1/3 are blue, and 3/7 of the remainder are green. If there are 27 green caps,

how many caps are there altogether.

1 answer:

3241004551 [841]3 years ago

5 0

$\frac{1}{6}x+\frac{1}{3}x+\frac{3}{7}(x-(\frac{1}{6}x+\frac{1}{3}x))=x\\\frac{3}{7}(x-(\frac{1}{6}x+\frac{1}{3}x))=27\\\frac{3}{7}(x-(\frac{1}{2}x))=27\\\frac{3}{7}(\frac{1}{2}x)=27\\x=126$

126 caps

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Luba_88 [7]

Answer: No solution

Step-by-step explanation:

The red line is y=3x+7 and the blue line is y=3x+2

The lines do not intersect at any time. Therefore, this set of equations has no solution. I hope this helps! Pls mark brainliest!! :)

7 0

1 year ago

How does the slope of g(x) compare to the slope of f(x)?

Maru [420]

Answer:

The answer is 'The slope of g(x) is less than the slope of f(x)'

Step-by-step explanation:

Given the graphs of f(x) and g(x). we have to compare the slops of these two.

The graph of f(x) passes through the points (1,0) and (2,2)

∴ $\text{The slope of f(x)=}\frac{y_2-y_1}{x_2-x_1}=\frac{2-0}{2-1}=2$

The graph of g(x) passes through the points (0,2) and (2,3)

∴ $\text{The slope of g(x)=}\frac{y_2-y_1}{x_2-x_1}=\frac{3-2}{2-0}=\frac{1}{2}$

As $\frac{1}{2}$

This shows that the

The slope of g(x) is less than the slope of f(x).

8 0

3 years ago

Read 2 more answers

I want yall to get brainly points wahts 2x5 i know it equals 10 answer it tho

MakcuM [25]

The answer to 2x5 is 10 lol

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2 years ago

What are the coordinates of the centroid of a triangle with vertices A(−3, 1) , B(1, 6) , and C(5, 2) ? Enter your answer in the

kirza4 [7]

<u>ANSWER</u>: The centroid is (1,3)

<u>Explanation:</u>

The centroid is the intersection of the medians of the triangle.

So we need to find the equation of any two of the medians and solve simultaneously.

Since the median is the straight line from one vertex to the midpoint of the opposite side, we find the midpoint of any two sides.

We find the midpoint of AC using the formula;

$N=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

$N=(\frac{-3+5}{2}, \frac{1+2}{2})$

$N=(\frac{2}{2}, \frac{3}{2})$

$N=(1, \frac{3}{2})$

The equation of the median passes through $B(1,6)$ and $N=(1, \frac{3}{2})$ .

This line is parallel to the y-axis hence has equation

$x=1$ -------first median.

We also find the midpoint M of BC.

$M=(\frac{1+5}{2}, \frac{6+2}{2})$

$M=(\frac{6}{2}, \frac{8}{2})$

$M=(3, 4)$

The slope of the median, AM is

$Slope_{AM}=\frac{4-1}{3--3}$

$Slope_{AM}=\frac{3}{6}$

$Slope_{AM}=\frac{1}{2}$

The equation of the median AM is given by;

$y-y_1=m(x-x_1)$

We use the point M and the slope of AM.

$y-4=\frac{1}{2}(x-3)$

$2y-8=(x-3)$

$2y-x=-3+8$

$2y-x=5$ -------Second median

We now solve the equation of the two medians simultaneously by putting $x=1$ in to the equation of the second median.

$2y-1=5$

$2y=5+1$

$2y=6$

$y=3$

Hence the centroid has coordinates $(1,3)$

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2 years ago

Read 2 more answers

The probability that a person in the United States has type B+ blood is 10%. Four un-related people in the United States are se

marysya [2.9K]

Answer:

a. 0.0001

b. 0.6561

c. 0.3439

d. B. The event in part (a) is unusual because its probability is less than or equal to 0.05.

Step-by-step explanation:

a. # We are given that the probability that a person in the United States has Type B+ blood = 0.10. Also we are told that four unrelated people in the United States are selected at random.

#We have to find here the probability that all four have type B+ blood.

Since the events are independent, we have :

Probability that all four have B+ blood = 0.10 x 0.10x 0.10x0.10

= 0.0001

Therefore, the probability that all four have type B+ blood is 0.0001

b. We have to find the probability that none have B+ blood. Using the complementary law of probability we have:

Probability that blood type is not B+ = 1 - 0.10= 0.90

Therefore, the probability that none have B+ blood

= 0.90 x 0.90 x 0.90x0.90=0.6561

Therefore, the probability that none have B+ blood is 0.6561

c. We have to find the probability that at least one of the four have B+ blood.

#The probability that at least one of the four have B+ blood = 1 - Probability that none have B+ blood type

=1-0.6561=0.3439

Therefore,the probability that at least one of the four has type B+ blood is 0.3439

d. An event is considered unusual if the probability of the event is small or less than 0.05 . We note that event a is the only small probabilty and is less than 0.05.

-a is thus considered unusual(the rest are all usual events)

6 0

2 years ago