When £13000 is increased by 11% the new value becomes to £14430
Answer:
25
Step-by-step explanation:
When dividing by fractions, you can multiply by the opposite reciprocal.
5 ÷ 1/5
5 x 5/1
25
Height of the water increasing is at rate of 
<h3>How to solve?</h3>
With related rates, we need a function to relate the 2 variables, in this case it is clearly volume and height. The formula is:

There is radius in the formula, but in this problem, radius is constant so it is not a variable. We can substitute the value in:

Since the rate in this problem is time related, we need to implicitly differentiate wrt (with respect to) time:

In the problem, we are given
So we need to substitute this in:

Hence, Height of the water increasing is at rate of 
<h3>Formula used: </h3>

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Not sure but I think it's (3)
Answer:
Base=8 feet
Height=17 feet
Step-by-step explanation:
Let
Base=x
Height=3x-7
Area=68 square feet
Area of the sail boat=1/2 * base * height
68 = 1/2 * x * (3x-7)
Cross product
68 * 2 =(1) * (x) * (3x-7)
136 = 3x^2 - 7x
3x^2 - 7x - 136=0
Using quadratic formula
x= -b +or- √b^2 - 4ac / 2a
= -(-7) +or- √(-7)^2 - (4)(3)(-136) / 2(3)
= 7 +or- √49 - (-1632) / 6
= 7 +or- √49+1632) / 6
= 7 +or- √1681 / 6
=7 +or- 41 /6
x= 7+41 / 6 or 7-41 / 6
=48/6 or -34/6
=8 or -17/3
Answer:
Step-by-step explanation:
Let
Base=x
Height=3x-7
Area=68 square feet
Area of the sail boat=1/2 * base * height
68 = 1/2 * x * (3x-7)
Cross product
68 * 2 =(1) * (x) * (3x-7)
136 = 3x^2 - 7x
3x^2 - 7x - 136=0
Base of the boat can't be a negative value
Therefore,
Base = x = 8 feet
Height= 3x-7
=3(8)-7
=24-7
=17 feet