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3 years ago

Which property is it?

Mathematics

2 answers:

ddd [48]3 years ago

7 0

Answer is G
with or without the 10, you are going to get 5 as your answer to the equation

pishuonlain [190]3 years ago

4 0

The Correct Answer is G
(Commutative Property Of Multiplication)

{Hope it helps :D}

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542 increased by 1/4 of itself is?

Bas_tet [7]

542(1+1/4)

542(4/4+1/4)

542(5/4)

677.5

5 0

4 years ago

Read 2 more answers

SPIRAL REVIEW - Find the value of the expression below.<br><br> 96 ÷ 4² + (25×2) - 15 - 3

Lunna [17]

Answer:

Step-by-step explanation:

96/16

+(25)(2)−15−3

=6+(25)(2)−15−3

=6+50−15−3

=56−15−3

=41−3

=38

3 0

3 years ago

Im so bad at math. Help please!

Ulleksa [173]

Answer is C. Granted gas prices are fixed. if you buy 1 gallon.. price is x. if you buy 2 gallons, price is 2x. and so on. constant rate of change.

6 0

3 years ago

8 to 11 do it with equations thx

Alenkasestr [34]

Answer:

Step-by-step explanation:

8. $4\geq x+\frac{3}{4}$

$4(4\geq x+\frac{3}{4} )$

$16\geq 4x + 3$

$-3$ $-3$

$13\geq 4x$

$\frac{13}{4}\geq \frac{4x}{4}$

$\frac{13}{4} \geq x = x\leq \frac{13}{4}$

$x\leq \frac{13}{4}=3.25$

9. $x-3\leq -8$

$+3$ $+3$

$x\leq -5}$

10. $4\leq x-7$

$+7$ $+7$

$11\leq x=x\geq 11$

11. 6.9 < x - 2.3

+ 2.3 + 2.3

9.2 < x = x > 9.2

Hope this helps!

5 0

2 years ago

An industry representative claims that 10 percent of all satellite dish owners subscribe to at least one premium movie channel.

Greeley [361]

Answer: 1) 0.6561 2) 0.0037

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x success in n trials is given by :-

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

, where p =Probability of getting success in each trial.

As per given , we have

The probability that any satellite dish owners subscribe to at least one premium movie channel. : p=0.10

Sample size : n= 4

Let x denotes the number of dish owners in the sample subscribes to at least one premium movie channel.

1) The probability that none of the dish owners in the sample subscribes to at least one premium movie channel = $P(X=0)=^4C_0(0.10)^0(1-0.10)^{4}$

$=(1)(0.90)^4=0.6561$

∴ The probability that none of the dish owners in the sample subscribes to at least one premium movie channel is 0.6561.

2) The probability that more than two dish owners in the sample subscribe to at least one premium movie channel.

= $P(X>2)=1-P(X\leq2)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\= 1-[0.6561+^4C_1(0.10)^1(0.90)^{3}+^4C_2(0.10)^2(0.90)^{2}]\\\\=1-[0.6561+(4)(0.0729)+\dfrac{4!}{2!2!}(0.0081)]\\\\=1-[0.6561+0.2916+0.0486]\\\\=1-0.9963=0.0037$

∴ The probability that more than two dish owners in the sample subscribe to at least one premium movie channel is 0.0037.

8 0

3 years ago