2e^(x+3)=10
e^(x+3)=5
ln[e^(x+3)]=ln 5
(x+3)ln e=ln 5
(x+3)=ln 5
x=(ln 5)-3
Answer: x=(ln 5) - 3
Rational zero theorem is all combinations of p(factors of the constant) divided by q(factors of the first coefficient)
factors of 8 are 1, 2, 4, 8
factors of 2 are 1, 2
so all possible rational zeros are all combinations of p/q
+/- 1/1, 1/2, 2/1, 2/2, 4/1, 4/2, 8/1, 8/2
Now there are some repeats in there so you have to leave those out and once we do that we get
+/- 1, 1/2, 2, 4, 8
Remember all those are plus OR minus
L(w) = area of rectangle
x(x+4)
If x = 12...
12(12+4) Distribute the 12 to both terms inside parenthesis.
144 + 48 Add
192 Final Area
Answer:
$330
Step-by-step explanation:
Please see the attached picture for the full solution.
☆ There is no need to round the answer off to the nearest cents as the answer is a whole number.
Answer:
2 out of 5
Step-by-step explanation:
I believe that 96/240 needs to be simplified until it cant anymore, an that is the probability because they both fit three, I will divide by three.
96/3=32
240/3= 80
<u>32/80</u>
2
16/40 then because they both fit four, Ill do four.
4/10then 2 again
2/5 so, it is 2 out of five
please correct me if I am wrong, I was never good at probabilities, but I am better now.
