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3 years ago

PLEASE HELP ME I FORGOT HOW TO DO THIS PLZ SHOW THE WORK TOO

Mathematics

2 answers:

Cerrena [4.2K]3 years ago

8 0

Substitute the input (x) numbers for x . Example: y= 5x substitute -3 for X
5 x -3 = -15. So there's your first answer for the first chart.

Sveta_85 [38]3 years ago

5 0

The first one is -2 because you wanna try to get to the value of k and -2•-3= 5

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14 - 2x = 3(x - 2) what is the answer

RSB [31]

The answer will be x=4

4 0

3 years ago

The weights of four packets of sugar are shown below:

bekas [8.4K]

The lightest it will weigh will be 4.3 Pounds

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3 years ago

If a point P(x,y) is the equidistant from the points A(2,3) and B(6,1), find the equation of locus of moving point P.

jekas [21]

Answer:

$y=2x-6$

Step-by-step explanation:

A locus can be defined as a curve or figure formed by all the points satisfying a particular equation of the relation between coordinates.

The condition stated in the question is such that a generic (x,y) point of the curve is equidistant from the points A(2,3) and B(6,1).

The distance d1 from (x,y) to (2,3) is:

$d_1=\sqrt{(x-2)^2+(y-3)^2}$

The distance d2 from (x,y) to (6,1) is:

$d_2=\sqrt{(x-6)^2+(y-1)^2}$

Since d1=d2:

$\sqrt{(x-2)^2+(y-3)^2}=\sqrt{(x-6)^2+(y-1)^2}$

Squaring both sides:

$(x-2)^2+(y-3)^2=(x-6)^2+(y-1)^2$

Operating:

$x^2-4x+4+y^2-6y+9=x^2-12x+36+y^2-2y+1$

Simplifying all the squares:

$-4x+4x+4-6y+9=-12x+36-2y+1$

Moving the variables to the left side and the numbers to the right side:

$-4x+12x-6y+2y=36+1-4-9$

Simplifying:

$8x-4y=24$

Dividing by 4:

$2x-y=6$

Or, equivalently:

$\boxed{y=2x-6}$

7 0

3 years ago

Solve the system by graphing.

choli [55]

Answer:

(4,-5)

Step-by-step explanation:

6 0

3 years ago

PLS HELP! i will mark you the brainliest!!!

forsale [732]

1. v = 4.5

2. Whatever variable = 6.3

3. g = 0.4

4. a = 17.4

Hope it helps! :)

8 0

2 years ago