Question

Jar 1 has 12 marbles in it. It has 2 yellow marbles, 4 red marbles, and 6 blue marbles. Jar 2 has 8 cubes in it. It has 2 green cubes, 2 red cubes, and 4 yellow cubes. Find the probability of drawing out a blue marble and a green cube without looking.

Answer 1

Answer:

$\dfrac{1}{8}$

Step-by-step explanation:

To find the probability of drawing a blue marble and green cube, we need to first find out their probabilities in each jar separately.

In Jar 1 there are:

2 yellow + 4 red + 6 blue = 12 total marbles.

Now the probability of drawing a blue marble in Jar 1 will be:

$\dfrac{6}{12}or\dfrac{1}{2}$

Now in Jar 2 there are:

4 yellow + 2 red + 2 green = 8 total cubes.

Now the probability of drawing a green cube in Jar 2 will be:

$\dfrac{2}{8}or\dfrac{1}{4}$

Now we simply multiply both fractions together to find the probability of drawing a blue marble and a green cube.

$Total Probability=\dfrac{1}{2}*\dfrac{1}{4}$

$Total Probability=\dfrac{1}{8}$

So there is a $\dfrac{1}{8}$ chance that we will draw a blue marble and a green cube from both jars without looking.