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Mars2501 [29]
3 years ago
6

You and a friend both would like a salad and a small drink. Between the two of you, you have $8.00. A salad costs $2.49 and a sm

all drink is $0.99. Can either of you have a second salad or a drink?
Mathematics
1 answer:
lesya692 [45]3 years ago
7 0

Answer: Yes, the amount can buy either of them a second salad or a drink.

Step-by-step explanation:

Since a salad cost $2.49 and a bottle of drink cost $0.99, therefore for both of them the total amount they need to spend is (2×$2.49)+(2×$0.99)

= $4.98+$1.98

= $6.96

This is the amount for both of them to get a first salad and a drink.

Since they both have $8.00 with them, their balance will be $8.00-$6.96 which is $1.04

The balance can buy one of them second drink then that is $0.99. So yes, the amount can buy either of them a second salad or a drink.

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Help answer this question asap!!!!!!!!1
kkurt [141]

Answer:

169.50

Step-by-step explanation:

7 0
3 years ago
12) Find the sum, S7 for the geometric series {1 + 5 + 25 + - + 15625).
zhenek [66]

<u>Understanding:</u>

The sum of a geometric series is, a+ar+ar^2+ar^3+..., with a being the start point and r is the common ratio. We can also use the following formula to make life easier S_n=a\frac{1-r^n}{1-r}, a is your start point, r is the common ratio, and n is the number of terms, which in our case is S7.

<u>Solution:</u>

Our start point is 1, a=1,

The common ratio is 5, r=5,

And finally, the number of terms is 7, n=7.

S_n=a\frac{1-r^n}{1-r} \\=(1)\frac{1-(5)^{(7)}}{1-(5)} \\=\frac{1-78125}{1-5} \\=\frac{-78124}{-4}\\=19531

The answer is [A] 19531.

7 0
3 years ago
Read 2 more answers
Mrs. Low has 12 bags, each containing 25 sweets. She divides the sweets among 30 boys equally. How many sweets does each boy get
irakobra [83]
Each boy gets 10 sweets.

12×25=300÷30=10//
6 0
3 years ago
I need to find the greatest common factor of <img src="https://tex.z-dn.net/?f=40s%5E3t%5E5" id="TexFormula1" title="40s^3t^5" a
solong [7]

Answer:

\large\boxed{GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=2s^3t^4}

Step-by-step explanation:

40s^3t^5=\boxed2\cdot2\cdot2\cdot5\cdot \boxed{s\cdot s\cdot s}\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\\\\2s^4t^4=\boxed2\cdot  \boxed{s\cdot s\cdot s}\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\\\\14s^6t^6=\boxed2\cdot7\cdot  \boxed{s\cdot s\cdot s}\cdot s\cdot s\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\cdot t\\\\GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=\boxed2\cdot  \boxed{s\cdot s\cdot s}\cdot\boxed{t\cdot t\cdot t\cdot t}=2s^3t^4

7 0
3 years ago
A diagonal brace is to be placed in the wall of a room. the height of the wall is 6 ft, and the wall is 12 ft long. what is the
Varvara68 [4.7K]
We know that
Applying the Pythagoras Theorem
c=²=a²+b²
where c is the diagonal of the wall
a=12 ft
b=6 ft
c²=12²+6²-----> c²=144+36-----< c²=180-----> c=√180------> c=6√5 ft

the answer is
<span>the exact length of the brace is 6</span>√5 ft
8 0
3 years ago
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