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Sophie [7]
3 years ago
9

Please solve all the answers down below, and include how you got your answers.

Mathematics
1 answer:
Andrej [43]3 years ago
5 0

Answer:

1. 4 is missing

2. 283 is a odd number

3. 23

4. no idea

5. D

6. A

I cant see the rest

Step-by-step explanation:

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Let $A = (4,-1)$, $B = (6,2)$, and $C = (-1,2)$. There exists a point $X$ and a constant $k$ such that for any point $P$,
goldfiish [28.3K]

Answer:

k=32

Step-by-step explanation:

Given the points:

A = (4,-1)$, $B = (6,2)$, and $C = (-1,2)$.

The first step is to find the <u>Centroid</u> of the triangle.

Centroid, X

=\left(\dfrac{x_1+x_2+x_3}{3} ,\dfrac{y_1+y_2+y_3}{3} \right)\\=\left(\dfrac{4+6+(-1)}{3} ,\dfrac{-1+2+2}{3} \right)\\=\left(\dfrac{9}{3} ,\dfrac{3}{3} \right)=(3,1)

Next, let P be a point (x,y)

Using the <u>distance formula, </u>\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}<u />

<u />PA^2=(x-4)^2+(y-(-1))^2\\PB^2=(x-6)^2+(y-2)^2\\PC^2=(x-(-1))^2+(y-2)^2\\PX^2=(x-3)^2+(y-1)^2\\<u />

On Substitution into: PA^2 + PB^2 + PC^2 = 3PX^2 + k

(x-4)^2+(y-(-1))^2+(x-6)^2+(y-2)^2+(x-(-1))^2+(y-2)^2=3[(x-3)^2+(y-1)^2]+k

Let us simplify the LHS first

\\LHS: x^2-8x+16+y^2+2y+1+x^2-12x+36+y^2\\-4y+4+x^2+2x+1+y^2-4y+4\\=3x^2-18x+3y^2-6y+62

Also, the Right Hand Side

RHS:3[(x-3)^2+(y-1)^2]+k\\=3[x^2-6x+9+y^2-2y+1]+k\\=3x^2-18x+27+3y^2-6y+3+k\\=3x^2+3y^2-18x-6y+30+k

Therefore:

3x^2-18x+3y^2-6y+62=3x^2+3y^2-18x-6y+30+k\\k=3x^2-18x+3y^2-6y+62-3x^2-3y^2+18x+6y-30\\k=3x^2-3x^2+3y^2-3y^2-18x+18x+62-30\\k=32

7 0
3 years ago
I have to find the probability is stuff please help
Marysya12 [62]

Answer:

1.) 1/2 or 50%

Step-by-step explanation:

Lemme take sum time to do 2, 3, and 4!

6 0
3 years ago
2/7 divided by 6, fastest answer (and correct) gets brainest.
laiz [17]

Answer:

0.047619

P.S. do you need to round?

3 0
3 years ago
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You are a space alien. You visit planet Earth and abduct 97 chickens, 47 cows, and 77 humans. Then, you randomly select one Eart
ale4655 [162]

Answer:

there are 97 + 47 + 77 = 221 creatures from Earth in the alien spaceship.

the probability that a human being is chosen at random = 77 / 221 = 0.3484 = 34.84%

the probability that a chicken is chosen at random = 97 / 221 = 0.4389 = 43.89%

the probability of choosing a cow at random = 100% - 34.84% - 43.89% = 21.27%

4 0
3 years ago
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Part C. Cindy also wants to buy some plants for her garden. She has at most $30 to spend on the plants. She buys 6 tomato plants
hoa [83]

Answer:

i dunoo

Step-by-step explanation:

6 0
3 years ago
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