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3 years ago

11

I need help with this math problem. Please someone help me if they can.

2 answers:

My name is Ann [436]3 years ago

7 0

The equation for the surface are of a cylinder is 2pi(r)(h)+2pi(r)^2
SA=2 pi(4)(12.4)+2 pi(4)^2
The surface area is 412.2, which for you is rounded to 412 cm^2

Veronika [31]3 years ago

6 0

The answer is <span>412

hope this helps
can i plz get brainliest </span>

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2. 144 in.<br> C<br> yd<br> Pls someone help I have a test tomorrow

MatroZZZ [7]

what are you asking im confused

3 0

3 years ago

Read 2 more answers

The third-grade gymnastics team has 279 points. In order to place in the top three teams, they'll need a score of 425 or more. H

Degger [83]

425-279=146
They would need 146+

5 0

3 years ago

PLEASE SOMEONE HELP AND SHOW UR WORK..

Sonbull [250]

Answer: The answer is 2,713 in³

The volume (V) of the prop is the sum of the volume of cone (V1) and half of the volume of the sphere (V2): V = V1 + 1/2 * V2

Volume of the cone is:

V1 = π r² h / 3

According to the image,

h = 14 in

r = 9 in

and

π = 3.14

V1 = 3.14 * 9² * 14 / 3 = 1,186.92 in³

The volume of the sphere is:

V2 = π r³ * 4/3

According to the image,

r = 9 in

and

π = 3.14

V2 = 3.14 * 9³ * 4/3 = 3,052.08 in³

The volume of the prop is:

V = V1 + 1/2 * V2

V = 1,186.92 in³ + 1/2 * 3,052.08 in³

V = 1,186.92 in³ + 1,526.04 in³

V = 2,712.96 in³ ≈ 2,713 in³

4 0

3 years ago

Arrange the cones in order from lease volume to greatest volume

bearhunter [10]

Answer:

Volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

cone with DIAMETER of 18 & height of 10

cone with RADIUS of 10 & height of 9

cone with RADIUS of 11 & height of 9

cone with DIAMETER of 20 & height of 12

Step-by-step explanation:

Let $V_{2}. V_{3}. and\ V_{4}.$ be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

Given:

$d_{1} = 20\ and\ h_{1}=12$

$d_{2} = 18\ and\ h_{2}=10$

$r_{3} = 10\ and\ h_{3}=9$

$r_{4} = 11\ and\ h_{14}=9$

Arrange the cones in order from lease volume to greatest volume.

Solution:

The volume of the cone is given below.

$V=\pi r^{2} \frac{h}{3}$ ----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for $d_{1} = 20\ and\ h_{1}=12$

$r_{1} = \frac{d_{1}}{2}$

$r_{1} = \frac{20}{2}=10\ units$

$V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}$

$V_{1}=\pi (10)^{2} \frac{12}{3}$

$V_{1}=\pi\times 100\times 4$

$V_{1}=400\pi\ units^{3}$

Similarly, for volume of the cone for $d_{2} = 18\ and\ h_{2}=10$

$r_{2} = \frac{d_{2}}{2}$

$r_{2} = \frac{18}{2}=9\ units$

$V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}$

$V_{2}=\pi (9)^{2} \frac{10}{3}$

$V_{2}=\pi\times 81\times \frac{10}{3}$

$V_{2}=\pi\times 27\times 10$

$V_{2}=270\pi\ units^{3}$

Similarly, for volume of the cone for $r_{3} = 10\ and\ h_{3}=9$

$V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}$

$V_{3}=\pi (10)^{2} \frac{9}{3}$

$V_{3}=\pi\times 100\times 3$

$V_{3}=\pi\times 300$

$V_{3}=300\pi\ units^{3}$

Similarly, for volume of the cone for $r_{4} = 11\ and\ h_{4}=9$

$V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}$

$V_{4}=\pi (11)^{2} \frac{9}{3}$

$V_{4}=\pi\times 121\times 3$

$V_{4}=\pi\times 363$

$V_{4}=363\pi\ units^{3}$

So, the volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

7 0

3 years ago

Shelly runs 2.5 miles in 18 minutes. What is her mile time in minutes?

gregori [183]

Answer:

7.2 minutes

Step-by-step explanation:

You can just divide 18 minutes by 2.5, and you will get 7.2 minutes per mile. Hope it helps!

5 0

3 years ago