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3 years ago

I don’t understand this one

Mathematics

1 answer:

Masja [62]3 years ago

5 0

Answer:

see below

Step-by-step explanation:

Put -1 where x is in each expression and evaluate it.

You will find that the expression is zero when the numerator is zero. And you will find the numerator is zero when it has a factor that is equivalent to ...

(x +1)

Substituting x=-1 into this factor makes it be ...

(-1 +1) = 0

Evaluating the first expression, we have ...

$\dfrac{4(x+1)}{(4x+5)}=\dfrac{4(-1+1)}{4(-1)+5}=\dfrac{4\cdot 0}{1}=0$

This first expression is one you want to "check."

You can see that the reason the expression is zero is that x+1 has a sum of zero. You can look for that same sum in the other expressions. (The tricky one is the one with the factor (x -(-1)). You know, of course, that -(-1) = +1.)

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3 years ago

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3 years ago

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jolli1 [7]

Answer:

4 different answers

Step-by-step explanation:

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3 years ago

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djyliett [7]

Answer:

Step-by-step explanation:

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3 years ago

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AlladinOne [14]

Answer:

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Step-by-step explanation:

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