Question

Which graph could represent the function f(x) = (x + 3.8)2 – 2.7? On a coordinate plane, a parabola opens up. It starts in quadrant 1, crosses the x axis where the vertex is in quadrant 4, and crosses the x-axis back into quadrant 1. On a coordinate plane, a parabola opens up. It starts in quadrant 2 and does not cross the x-axis or y-axis. On a coordinate plane, a parabola opens up. It starts in quadrant 1 and does not cross the x-axis or y-axis. On a coordinate plane, a parabola opens up. It starts in quadrant 2, crosses the x axis where the vertex is in quadrant 3, and crosses the x-axis back into quadrant 2.

Answer 1

Answer:

The last choice is correct.

Step-by-step explanation:

The given function is

$f(x) = {(x + 3.8)}^{2} - 2.7$

This is a parabola with a=1>0.

The graph will therefore open up.

By comparing to

$f(x) = a(x - h)^{2} + k$

The vertex is at (h,k)= (-3.8,-2.7)

Therefore the graph crosses the x-axis and the y-axis.

Also the vertex is in the 3rd quadrant because both x and y are negative in this quadrant.

Answer:

On a coordinate plane, a parabola opens up. It starts in quadrant 2, crosses the x axis where the vertex is in quadrant 3, and crosses the x-axis back into quadrant 2.

Answer 2

Answer:

d.

Step-by-step explanation: