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Scorpion4ik [409]
3 years ago
10

Use a calculator to find the approximate value of arcsin(0.682)

Mathematics
2 answers:
Inessa05 [86]3 years ago
4 0

I believe it is 43 degrees

Anarel [89]3 years ago
3 0
I hope this helps you

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Helppppppppppppppppppppp
Komok [63]
The answer is A. $77.70

Just multiply 5×3=15 then multiply $5.18×15=77.7

I hope this helps.
4 0
4 years ago
How to draw a model for 0.78
kondor19780726 [428]
Hi Annabanna11!
You can draw a model for 0.78 by drawing 100 parts and coloring 78 of them! 0.78=78/100=78%
I hope this helps:)
6 0
4 years ago
Read 2 more answers
Y = f(x) has the derivative f'(x) = (x + 1)²(x + 3)(x² + 2mx + 5) with ∀x∈i.
maksim [4K]

9514 1404 393

Answer:

  m ≥ -√5

Step-by-step explanation:

If g(x) = f(|x|) for x∈i, then g(x) = f(x) for x∈ℝ: x ≥ 0.

f'(x) is 5th-degree, so f(x) is 6th-degree, meaning it is generally U-shaped. Since we're only concerned with x ≥ 0, we want to make sure f'(x) has no real zeros of odd multiplicity such that x > 0. The given factors of f'(x) make it have real zeros at x = -3 and x = -1.

For the last factor, (x² +2mx +5) to have no positive real zeros of odd multiplicity, we must have m ≥ 0 or the discriminant ≤ 0. The discriminant is ...

  d = b² -4ac = (2m)² -4(1)(5) = 4m² -20 . . . . . discriminant of the last factor

  d ≤ 0 . . . . . . . . . . the condition for no real zeros

  4m² -20 ≤ 0

  m² -5 ≤ 0 . . . . . . divide by 4

  m² ≤ 5 . . . . . . . . .add 5

  |m| ≤ √5 . . . . . . . take the square root

This tells us there will be a positive real zero of multiplicity 2 in f'(x) when m = -√5, and there will be no positive real zeros for -√5 < m < 0

There will be no odd-multiplicity positive real zeros in the derivative function f'(x) as long as m ≥ -√5. This means the slope of f(x) is non-negative for x ≥ 0, hence f(|x|) has its only minimum at x=0.

_____

<em>Additional comment</em>

The multiplicity of the zeros of f'(x) is important because the derivative will only change sign where the multiplicity is odd. When the discriminant of (x²+2mx+5) is zero, the associated positive real zero will have multiplicity 2, hence f'(x) will not change sign there.

3 0
3 years ago
Circle A and circle B are congruent. CD is a cord of both circles. if AB = 24 inches in the radius is 13 inches how long is CD A
Nitella [24]

Option A

Length of CD is 10 inches

<u><em>Solution:</em></u>

The diagram is attached below

Given that, Circle A and circle B are congruent

CD is a cord of both circles

AB = 24 inches

Radius = 13 inches

To find: length of CD

Draw a straight line connecting A and C

AC represents the radius of circle. Also given that radius is 13 inches, So AC = 13 inches

Given in question that AB = 24 inches

Therefore from figure, AO = AB/2 = 24/2 = 12

AO = 12

Let "b" be the length of CO

Therefore, CD = CO + OD = b + b

AOC forms a triangle, so we can use pythogoras theorem

Pythagorean theorem, states that the square of the length of the hypotenuse is equal to the sum of squares of the lengths of other two sides of the right-angled triangle.

By above definition for triangle AOC

AC^2 = AO^2 + OC^2

Substituting AC = 13 and AO = 12 and OC = b

13^2 = 12^2 + b^2\\\\b^2 = 169 - 144\\\\b^2 = 25\\\\b = 5

<em><u>Thus length of CD is:</u></em>

CD = b + b = 5 + 5 = 10

Thus length of CD is 10 inches

8 0
3 years ago
Do these ratios form a proportion?
telo118 [61]

Answer:

No, because both of them will never be able to match; become equivalent. You would have to multiply 2 different numbers to make them match, meaning they would not be proportional. For a comparison to be proportional, the ratio you are trying to simplify to must be achieved by multiplying 2 numbers from the previous ratio by one LCD.

\frac{3\cdot 4}{7 \cdot 3} = \frac{12}{21}

They are<em> able</em> to make 12/21, but that does not mean they are proportional.

6 0
2 years ago
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