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Zigmanuir [339]
3 years ago
12

The diameter of a circle is 6units. What is the radius of the circle?

Mathematics
2 answers:
Agata [3.3K]3 years ago
7 0

Answer:

Using the formula

d=2r

Solving for r

r = d/2 = 6/2 =3

r = 3

Westkost [7]3 years ago
3 0

Answer: 3 units

Answer is provided in the image attached.

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of A squirrel’s hidden nuts, for every 5 that get found, there are 3 that do not get found. A squirrel hid 40 nuts all together.
den301095 [7]

Answer:

The answer is 15

Step-by-step explanation:

because so the squirrel hid 40

so

|||||   ||| 8

|||||   ||| 16

|||||   ||| 24

|||||   ||| 32

|||||    ||| 40

so if you count the all the group of 3 that will get your answer.  

let me know if this make sense.

8 0
4 years ago
I need help <br> 22 points to whoever helps me
Olenka [21]

Answer:

12 3/4 same slope fro both

13 DE = 5, CB = 10

14 see below

Step-by-step explanation:

12.  the slopes are the same

D(0, 3)  E(4, 6) slope is (change in y)/(change in x)

   change in y = 3 to 6 is a change of +3

   Change in x = 0 to 4 is a change of +4

slope is 3/4

13  To fine lengths you can distance formula or Pythagorean theorem (spoiler: they are related to each other)  

DE² = 3² + 4²

DE² = 9 + 12

DE² =  25

√DE² = √25 = 5

DE = 5

and

CB² = 6² + 8²

CB² = 36 + 64

CB² = 100

√CB² = √100 = 10

CB = 10

14.   since the slopes are the same are DE is 1/2 or CB its is the mid segment.  because (taken from mathopenref.com/trianglemidsegment.html)

The midsegment is always parallel to the third side of the triangle. In the figure above, drag any point around and convince yourself that this is always true.

The midsegment is always half the length of the third side. In the figure above, drag point A around. Notice the midsegment length never changes because the side BC never changes.

A triangle has three possible midsegments, depending on which pair of sides is initially joined.

6 0
3 years ago
How do you do this question?
Molodets [167]

Answer:

C. y₂ = (1 + (t/n))²

Step-by-step explanation:

yₙ₊₁ = yₙ + Δt F(tₙ, yₙ)

yₙ₊₁ = yₙ + Δt yₙ

yₙ₊₁ = yₙ + (t/n) yₙ

When n=0:

y₁ = y₀ + (t/n) y₀

y₁ = 1 + (t/n)

When n=1:

y₂ = y₁ + (t/n) y₁

y₂ = 1 + (t/n) + (t/n) (1 + (t/n))

y₂ = 1 + (t/n) + (t/n) + (t/n)²

y₂ = 1 + 2(t/n) + (t/n)²

y₂ = (1 + (t/n))²

4 0
3 years ago
24 students in Christine's class are wearing tennis shoes there are 30 students in the class Christine says that 70% of the stud
saw5 [17]
No she not correct. 80% of the students are wearing tennis shoes
8 0
3 years ago
What is the value of x in the equation 3x -1/9<br> y = 18, when y = 27?<br> 5<br> 7<br> 45 63
almond37 [142]

Answer:

x=7

Step-by-step explanation:

we have

3x-\frac{1}{9}y=18

Substitute the value of y=27 in the equation and find the value of x

so

3x-\frac{1}{9}(27)=18

3x-3=18

3x=18+3

3x=21

x=7

4 0
3 years ago
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