All categories

4 years ago

Can anyone tell me how to do 28% of 32

Mathematics

2 answers:

Korvikt [17]4 years ago

8 0

Well you do 32 divided by 28% and get 8.96

Arisa [49]4 years ago

7 0

28% of 32 would be added so if you want your answer it would be 32.28

You might be interested in

Total consumption of fruit juice in a particular country in 2006 was about 2.05 billion gallons. The population of that country

Maslowich

Answer:

4.1 gallons per person

Step-by-step explanation:

The total consumption of fruit juice is 2.05 billion

The total population is 500 million

Therefore the average number of gallons fruit juice consumed per person can be calculated as follows

=total consumption/total population

= 2,050,000,000/500,000,000

= 4.1 gallons per person

6 0

3 years ago

Can abyone please give the answer to these questions?

Nady [450]

I don't know how to solve 11 but I guess I can solve 12 so I think those are the answers:

12.

(4, 53)

(5, 85)

4 0

3 years ago

Rewrite 7+ square root-121 in complex number notation

marin [14]

$7 + \sqrt{-121} = 7 + 11i$ because we define $\sqrt{-1} = i$

6 0

3 years ago

Can someone tell me how

gulaghasi [49]

the way I get the subsequent term, nevermind the exponents, the exponents part is easy, since one is decreasing and another is increasing, but the coefficient, to get it, what I usually do is.

multiply the current coefficient by the exponent of the first-term, and divide that by the exponent of the second-term + 1.

so if my current expanded term is say 7a³b⁴, to get the next coefficient, what I do is (7*3)/5 <----- notice, current coefficient times 3 divided by 4+1.

anyhow, with that out of the way, lemme proceed in this one.

$\bf ~~~~~~~~\textit{binomial theorem expansion} \\\\ \qquad \qquad (1+ax)^n\implies \begin{array}{llll} term&coefficient&value\\ \cline{1-3}&\\ 1&+1&(1)^n(ax)^0\\\\ 2&+\frac{(1)(n)}{1}\to n&(1)^{n-1}(ax)^1\\\\ 3&+\frac{n\cdot (n-1)}{2}&(1)^{n-2}(ax)^2 \end{array}$

so, following that to get the next coefficient, we get those equivalents as you see there for the 2nd and 3rd terms.

so then, we know that the expanded 2nd term is 24x therefore

$\bf n(1)^{n-1}(ax)1 = 24x\implies n(1)(ax)=24x\implies nax=24x\implies n=\cfrac{24}{a}$

we also know that the expanded 3rd term is 240x², therefore we can say that

$\bf \cfrac{n(n-1)}{2}~~(1)^{n-2}(ax)^2 = 240x^2\implies \cfrac{n(n-1)}{2}(1)(a^2x^2) = 240x^2 \\\\\\ \cfrac{(n^2-n)(a^2x^2)}{2}=240x^2\implies \cfrac{(n^2-n)(a^2)}{2}=\cfrac{240x^2}{x^2}\implies \cfrac{a^2n^2-a^2n}{2}=240 \\\\\\ a^2n^2-a^2n=480$

but but but, we know what "n" equals to, recall above, so let's do some quick substitution

$\bf a^2n^2-a^2n=480\qquad \boxed{n=\cfrac{24}{a}}\qquad a^2\left( \cfrac{24}{a} \right)^2-a^2\left( \cfrac{24}{a} \right)=480 \\\\\\ a^2\cdot \cfrac{24^2}{a^2}-24a=480\implies 24^2-24a=480\implies 576-24a=480 \\\\\\ -24a=-96\implies a=\cfrac{-96}{-24}\implies \blacktriangleright a = 4\blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ n=\cfrac{24}{a}\implies n=\cfrac{24}{4}\implies \blacktriangleright n=6 \blacktriangleleft$

7 0

4 years ago

I WILL MAKE BRAINLIEST!!!!

juin [17]

You forgot to add the picture. But if Mr. Vargas is the only one eating them the ANSWER is 7/8

6 0

3 years ago

Read 2 more answers