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Tom [10]
3 years ago
11

78.57142857 round up​

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
5 0

Answer:

It would be 79 as a whole number.

Step-by-step explanation:

78.<u>5</u>714857, you look at the number to the right to see if it is 5 or greater or less than 5.

If it is 5 or greater than. You would round it to 79

If not greater than 5. You round it down to 78 still.

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The following is a model showing the solution to an equation. x - 34 = 13 x - 34 + 34 = 13 + 34 x = 47 What property of equality
yanalaym [24]

Answer:

B.) Addition*Additive property of equality

Step-by-step explanation:

You add 34 to both sides of the equation to find what x was equal to

Hope I helped

8 0
3 years ago
Y-5=-1/2(x+7) (find the slope)
sashaice [31]

It's the slope-point formula:

y-y_1=m(x-x_1)

We have:

y-5=-\dfrac{1}{2}(x+7)

Therefore, the slope m=-\dfrac{1}{2}

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2 years ago
A company's records indicate that on any given day about 1% of their day shift employees and 3% of the night shift employees wil
shutvik [7]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

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4 0
3 years ago
1. Exercise 18, section 5.4. Compute 90, 91, 92, 93, 94 and 95. Make a conjecture about the units digit of 9n where n is a posit
Burka [1]

Answer:

n is a positive integer and here 90, 91, 92, 93, 94 and 95 is 9⁰ = 1

9¹ = 9

9² = 81

9³ = 729

9⁴ = 6561

9⁵ = 59049

so mathematical induction is prove given below.

Step-by-step explanation:

9⁰ = 1

9¹ = 9

9² = 81

9³ = 729

9⁴ = 6561

9⁵ = 59049

lets us consider by P (n) for the base case n = 0 then 9⁰ = 1  So P (1) is true

k ≥ 1so consider all integers

1≤l≤ k

There is a need to prove P (k+1)

if k is odd

9^k^+^1 =9^k.9.

9^k is 9 so

9^k = 9 +10m

then

9^k^+^1 = 9 ( 9 + 10m)

       =81 + 10 (9m)

so digit is 1 and k +1 is even

3 0
3 years ago
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