Answer:
The answer is "False".
Explanation:
The rule of thirds implies to the subject, which is not centered mostly on the picture because of new photography formats their shots. Its main object is a little off with one side by using a third-party principle, which draws your attention for the audience into another design, instead of only looking at the center. In another word, we can say that this rule is used as the definition to design the Crop tool to represent as an overlay.
Answer:
```
file = open("trips.txt","r")
file = file.split("\n")
trip_date = []
fuel_used = []
miles_traveled = []
for i in file:
trip_date.append(i.split(", ")[0])
for i in file:
fuel_used.append(i.split(", ")[1])
for i in file:
miles_traveled.append(i.split(", ")[2])
```
This should put the data in their own lists (i didn't test it) but im not going to solve everything for you. The rest is for you to tinker with. You shouldn't throw your question at us and expect an answer. This is the most that I will give you.
Explanation:
Answer:
import java.util.Arrays;
import java.util.Scanner;
public class num4 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("How many numbers? ");
int n = in.nextInt();
int []intArray = new int[n];
//Entering the values
for(int i=0; i<intArray.length;i++){
System.out.println("Enter the numbers");
intArray[i]=in.nextInt();
}
System.out.println(Arrays.toString(intArray));
int min =intArray[0];
for(int i =0; i<intArray.length; i++){
if(min>intArray[i]){
min = intArray[i];
}
}
System.out.println("The Minimum of the numbers is "+min);
}
}
Explanation:
- Using Java programming language
- Prompt the user for the number of values
- Using Scanner class receive and store in a variable
- Create an array of size n
- Using an for loop continuously ask the user to enter the integers
- Print the array of integers
- Using another for loop with an if statement, find the smallest element in the array of numbers
- Output the the smallest number
Answer:
Explanation:
C++ Code
#include <iostream>
#include <cstdlib>
using namespace std;
int main(){
double hour,minute;
cout<<"Enter Hours :";
cin>>hour;
cout<<"Enter Minutes :";
cin>>minute;
minute = minute+15;
if(minute >=60){
hour++;
minute = minute-60;
}
if(hour>23){
hour = 0;
}
cout<<"Hour: "<< hour<< " Minutes: "<<minute;
return 0;
}
Code Explanation
First take hours and minutes as input. Then add 15 into minutes.
If minutes exceeds from 60 then increment into hours and also remove 60 from minutes as hours already incremented.
Then check if hours are greater then 23 then it means new day is start and it should be 0.
Output
Enter Hours :9
Enter Minutes :46
Hour: 10 Minutes: 1
