We have been given that Layana’s house is located at
on a map. The store where she works is located at
.
We are asked to find the distance from Layana’s home to the store
We will use distance formula to solve our given problem.
Let us convert our given coordinates in improper fractions.
![2\frac{2}{3}\Rightarrow \frac{8}{3}](https://tex.z-dn.net/?f=2%5Cfrac%7B2%7D%7B3%7D%5CRightarrow%20%5Cfrac%7B8%7D%7B3%7D)
![7\frac{1}{3}\Rightarrow \frac{22}{3}](https://tex.z-dn.net/?f=7%5Cfrac%7B1%7D%7B3%7D%5CRightarrow%20%5Cfrac%7B22%7D%7B3%7D)
![-1\frac{1}{3}\Rightarrow -\frac{4}{3}](https://tex.z-dn.net/?f=-1%5Cfrac%7B1%7D%7B3%7D%5CRightarrow%20-%5Cfrac%7B4%7D%7B3%7D)
Now we will use distance formula to solve our given problem.
![D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
Upon substituting coordinates of our given point in above formula, we will get:
![D=\sqrt{(\frac{22}{3}-\frac{22}{3})^2+(\frac{8}{3}-(-\frac{4}{3}))^2}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B%28%5Cfrac%7B22%7D%7B3%7D-%5Cfrac%7B22%7D%7B3%7D%29%5E2%2B%28%5Cfrac%7B8%7D%7B3%7D-%28-%5Cfrac%7B4%7D%7B3%7D%29%29%5E2%7D)
![D=\sqrt{(0)^2+(\frac{8}{3}+\frac{4}{3})^2}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B%280%29%5E2%2B%28%5Cfrac%7B8%7D%7B3%7D%2B%5Cfrac%7B4%7D%7B3%7D%29%5E2%7D)
![D=\sqrt{0+(\frac{8+4}{3})^2}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B0%2B%28%5Cfrac%7B8%2B4%7D%7B3%7D%29%5E2%7D)
![D=\sqrt{(\frac{12}{3})^2}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B%28%5Cfrac%7B12%7D%7B3%7D%29%5E2%7D)
![D=\sqrt{(4)^2}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B%284%29%5E2%7D)
![D=4](https://tex.z-dn.net/?f=D%3D4)
Therefore, the distance from Layana's home to the store is 4 units and option A is the correct choice.
Answer:
![SE =\sqrt{\frac{p(1-p)}{n}}](https://tex.z-dn.net/?f=%20SE%20%3D%5Csqrt%7B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%7D)
And replacing we got:
![SE=\sqrt{\frac{0.75*(1-0.75)}{900}}= 0.014](https://tex.z-dn.net/?f=%20SE%3D%5Csqrt%7B%5Cfrac%7B0.75%2A%281-0.75%29%7D%7B900%7D%7D%3D%200.014)
Step-by-step explanation:
For this case we have the following info given:
represent the sample size selected
represent the population proportion
We want to find the standard error and we can use the distribution for the sample proportion and for this case since the sample size is large enough and we satisfy np>10 and n(1-p) >10 we have:
![\hat p \sim N (p,\sqrt{\frac{p(1-p)}{n}})](https://tex.z-dn.net/?f=%20%5Chat%20p%20%5Csim%20N%20%28p%2C%5Csqrt%7B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%7D%29)
And the standard error is given;
![SE =\sqrt{\frac{p(1-p)}{n}}](https://tex.z-dn.net/?f=%20SE%20%3D%5Csqrt%7B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%7D)
And replacing we got:
![SE= \sqrt{\frac{0.75* (1-0.75)}{900}}= 0.014](https://tex.z-dn.net/?f=%20SE%3D%20%5Csqrt%7B%5Cfrac%7B0.75%2A%20%281-0.75%29%7D%7B900%7D%7D%3D%200.014)
Answer:
-31 1/3 (answer choice 1)
Step-by-step explanation:
Let's begin by eliminating the fractions. Mult. all four terms by the LCD (8), obtaining:
-f - 6 - 2f = 88. Then -3f = 94, and f = -31 1/3
Answer:
2 people ordered salah
Step-by-step explanation:
#Total number of people in the class = 40
#Number of people who ordered chicken= 1/5 of the total number of people;
that is, ⅕×40=8
therefore 8 people ordered chicken.
#Number of people who ordered hamburgers= ¾of the total number of people.
that is; ¾×40=30
therefore 30 people ordered hamburgers.
#Number of people who ordered salad= total number of people - the sum of people who ordered chicken and hamburgers.
that is,
40 - ( 30 + 8 ),.
40 - 38 = 2
Answer:
B
Step-by-step explanation:
The graphs of the function and of its inverse function are always symmetrical about the line y = x.
The diagram shows the graph of the function f(x) (blue line).
The line with the equation y = x is the I quadrant bisector, so symmetrical graph to the grph of f(x) is red graph - graph of the function g(x).
Hence, correct option is B.