Given:
The expression is
To find:
The expression in repeated multiplication form and then write the expression as a power.
Solution:
We have,
The repeated multiplication form of this expression is
![=[(-8)\cdot (-8)\cdot (-8)]\cdot [(-8)\cdot (-8)\cdot (-8)\cdot (-8)]](https://tex.z-dn.net/?f=%3D%5B%28-8%29%5Ccdot%20%28-8%29%5Ccdot%20%28-8%29%5D%5Ccdot%20%5B%28-8%29%5Ccdot%20%28-8%29%5Ccdot%20%28-8%29%5Ccdot%20%28-8%29%5D)
Clearly, (-8) is multiplied seven times by itself. So,
Therefore, the repeated multiplication form of the given expression is 
and the expression as single power is 
.
Answer:Take a square root of sum of squares: c = √(a² + b²)
Step-by-step explanation:
Hey there!
So, therefore... the value 
in this number would be 
Answer:
Good luck on your assignment and enjoy your day!
~
Monthly salary with 56 hours training....hope this helps
- 4 - 4 + 4 ÷ 4
- 4 ÷ 4 + 4 ÷ 4
- (4 + 4 + 4) ÷ 4
- √4 + √4 + 4 - 4
- √4 + 4 + 4 ÷ 4
- √4 + 4 + 4 - 4
- 4 + 4 - 4 ÷ 4
- 4 + 4 + 4 - 4
- 4 + 4 + 4 ÷ 4
- √4 + √4 + √4 + 4
- 44/(√4 + √4)
- √4 + √4 + 4 + 4
- 44/4 + 4
- 4 + 4 + 4 + √4
- 44/4 + 4
- 4 * 4 * 4 ÷ 4
- 4 * 4 + 4 ÷ 4
- 4 * 4 - √4 + 4
- 4! - 4 - 4 ÷ 4
- 4 * (4 + 4 ÷ 4)
- 4! - 4 + 4 ÷ 4
- 4 * 4 + 4 + √4
- 4! - √4 + 4/4
- 4 * (√4 + √4 + √4)
- 4! + √2 - 4 ÷ 4
- 4! + √4 + 4 - 4
- 4! + √4 + 4 ÷ 4
- 4! + 4 + 4 - 4
- 4! + 4 + 4 ÷ 4
- 4! + √4 + √4 + √4
Lol, that took a while, hope it helps!
