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spin [16.1K]
3 years ago
14

If the radius of a sphere is increasing at the rate of 2 inches per second how fast

Mathematics
1 answer:
pogonyaev3 years ago
3 0
You haven't shared all of the question, so I'll guess that you want to find "how fast is the area of the sphere increasing?"

Area of a sphere = 4*pi*r^2

Rate of change of area of a sphere with respect to radius r:

               dA/dr = 8*pi*r*(dr/dt)

Here, that would come out to    

           dA/dr = 8*pi*r*(2 inches / sec)


If you meant, "how fast is the volume of the sphere increasing?" you'd need to use a different equation:


V = (4/3)*pi)*r^3

and go through a similar process.


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Alex787 [66]
Thank you for posting your question here at brainly. I hope the answer will help. Belowis the solution:

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If the difference between a number and 21 is divided by2, the result is 4 times the number. What is the number
Ostrovityanka [42]
(n-21)/2=4n is the equation

First, divide what is in the parentheses by 2
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Then, multiply the whole equation by 2 so we have all whole numbers
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Move N so that it is with 8n
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3 years ago
12
weeeeeb [17]

Answer:

2x + y = -4

Step-by-step explanation:

standard form of equation of straight line is

ax+by = c

that  is terms containing x and y should be  on LHS and constant term should be  on RHS

______________________________________________

Given equation

y + 1 = - 2x - 3

lets bring -2x on LHS ,

add 2x on lHS and RHS

y + 1  + 2x = - 2x - 3 + 2x

=> y + 1  + 2x = -3

on lHS, 1 is there which constant term lets bring it on RHS

subtract 1 from both sides

y + 1  + 2x  - 1= -3 -1

y + 2x = -4

rearranging it

2x + y = -4  (Answer)

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