The kite is approximately 78.80 feet off of the ground.
Explanation: If we assume that the string his held taut without any swag, we can use a right triangle to solve for the height of the kite. sin
θ
=
o
p
p
h
y
p
sin
52
o
=
h
100
f
t
100
sin
52
o
=
h
100
(
0.7880
)
=
h
78.80
f
t
=
h
The pattern is dividing by 2 every time so the next 3 numbers will be 1/8, 1/16, 1/32
11. x² - 7x = 0
x(x) - x(7) = 0
x(x - 7) = 0
x = 0 or x - 7 = 0
+ 7 + 7
x = 7
Solution Set: {0, 7}
12. 3x² - 4x = 20x + 27
+ 4x + 4x
3x² = 24x + 27
3x² - 24x - 27 = 0
x = -(-24) ± √((-24)² - 4(3)(-27))
2(3)
x = 24 ± √(576 + 324)
6
x = 24 ± √(900)
6
x = 24 ± 30
6
x = 4 ± 5
x = 4 + 5 or x = 4 - 5
x = 9 or x = -1
Solution Set: {9, -1}
2x + y = 7
y = -2x + 7 where slope m = -2 and b= y intercept = 7
Answer is C
slope : -2 and y intercept = 7
Answer: 68 ounces
Step-by-step explanation: 26x 2= 52 52+ 16= 68 ounces
