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Rom4ik [11]
3 years ago
8

How do you do this problem?

Mathematics
1 answer:
Sergio039 [100]3 years ago
4 0
Do the diameter of the rectangle the divid that by 2 and them multiply that time three

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Y’all I’m bored what y’all wanna do?
charle [14.2K]

Answer: eat, sleep, and watch anime

Step-by-step explanation: :)

4 0
3 years ago
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What is 0.001 as a percent
Masja [62]
1 tenth(1/10) of a percent or .1%
I know this because you multiply the decimal*100 to get the percent.
8 0
4 years ago
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A school concert has students tickets for $7 and nonstudents tickets for $12. If the school made $1973 selling 214 tickets? How
bearhunter [10]

Answer:

119 student tickets and 95 non-student tickets

Step-by-step explanation:

I did a trial-and-error solution.

I started with 107 students and 107 non-students:

(107*$7)+(107*$12) = $2033

It was too high, which tells us that there should be more who paid for the cheaper price.

I ended up with 119 and 95:

(119*$7)+(95*$12) = $1973

8 0
3 years ago
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Evaluate the permutation P(36,19)=____
kondaur [170]
Easy

nPr=\frac{n!}{(n-r)!}
here
36P19=\frac{36!}{(36-19)!}=
\frac{36!}{(17)!}=
\frac{36*35*34*33*32*31*30*29*28*27*26*25*24*23*22*21*20*19*18}{1}=
1045843337171591729971200000





6 0
4 years ago
Mr. Smith's wife works at an animal hospital. There is a equivalent fraction relationship between the number of dogs and cats in
dimulka [17.4K]

Answer:

There are 10 dogs in the kennels

Step-by-step explanation:

The equivalent fraction relationship between the number of dogs and cats in the kennels is 1/2.

Which means, if n_d the number of dods and n_c is the number of cats, then,

\frac {n_d}{n_c}=\frac{1}{2}\cdots(i)

Given that there are 20 cats, so n_c=20.

Now, from equation (i) we have,

\frac {n_d}{20}=\frac{1}{2}

\Rightarrow n_d=\frac{1}{2}\times 20

\Rightarrow n_d= 10.

Hence, there are 10 dogs in the kennels.

7 0
3 years ago
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