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Setler [38]
3 years ago
14

13. Find the total

Mathematics
1 answer:
never [62]3 years ago
5 0

Answer:

Time=2 years

Intrest=$4200

Rate=7.75%

Total amount(principle)=?

Now,

Total amount= Intrest×100/Time ×Rate

$4200×100/2×7.75

$420000/15.5

Therefore total amount=$27096.77

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Use the Distance Formula to answer the following questions. Round all of your answers to the nearest tenth (one decimal place).
zvonat [6]

Answer:

distance= 9 units to the nearest

Step-by-step explanation:

using the formula

√(∆x)^2+(∆y)^2

√73

= 8.5

= 9 units

4 0
3 years ago
Read 2 more answers
A farm that has 4 x 10^2 acres has 1.2 x 10^5 cattle. What is the average number of cattle per acre? Write the answer in Scienti
hram777 [196]

Step-by-step ex

4×10²

4×100

400


1.2×10⁵

  • 1.2×100,000

120,000


120,000/400

300


Your answer is: 300

4 0
3 years ago
How do you factor number 1 ?
kaheart [24]
What you did is correct.
8 0
3 years ago
100 POINTS AND BRAINLIYEST!!!
Helga [31]

See explanations below

Step-by-step explanation:

Chanel

(i) 90° counterclockwise and then dilation by a factor of 1/2

Trapezoid PQRS is given as :

P(6,-4) -------P'(4,6)

Q(2,-2)------Q'(2,2)

R(2,-6)-------R'(6,2)

S(6,-6)-------S'(6,6)

The transformation switches the position of (x,y) to and adds a -ve sign to the original y value

B. The new coordinates are : P'(4,6), Q'(2,2),R'(6,2) and S'(6,6)

The  rule for rotation 90° counterclockwise about the origin is (x,y)⇒(-y,x)

The rule for dilation with scale factor of 1/2 is (x,y)------(1/2x,1/2y)

P'(4,6) -----P''(2,3)

Q'(2,2)-----Q''(1,1)

R'(6,2)-----R''(3,1)

S'( 6,6)-----S''(3,3)

The dilation reduces the coordinates by 1/2

Preston

E. (i)Reflection over x-axis where the rule is : (x,y)----(x,-y)

(ii)Dilation by scale factor of 1/2 the rule is : (x,y)---(1/2x, 1/2y)

Applying reflection over x-axis rule;

P(6,-4) -----P'(6,4)

Q(2,-2)-----Q'(2,2)

R(2,-6)------R'(2,6)

S(6,-6)------S'(6,6)

The coordinates have changed in that a negative sign is added to the y-axis coordinate.

F. P'(6,4), Q'(2,2), R'(2,6) and S'(6,6)

G. Applying the dilation by scale factor of 1/2

P'(6,4)-------P''(3,2)

Q'(2,2)------Q''(1,1)

R'(2,6)------R''(1,3)

S'(6,6)------S''(3,3)

The coordinates of P'Q'R'S are divide by 2 to give coordinates of P''Q''R''S''

Comparing the answers to the final figure given

K(3,2)

L(1,1)

M(1,3)

N(3,3)

Preston is correct because his sequence proves trapezoid PQRS is similar to trapezoid KLMN.

Learn More

Reflection and dilation :brainly.com/question/13408902

Keywords :trapezoid, maps, rotate, counterclockwise, dilate,reflect,scale factor,shape, coordinate

#LearnwithBrainly

4 0
3 years ago
Read 2 more answers
Which of the equations are true identities? A. N ( n − 2 ) ( n + 2 ) = n 3 − 4 n B. ( x + 1 ) 2 − 2 x + y 2 = x 2 + y 2 + 1
ICE Princess25 [194]

Answer:

Both A and B are true identities

Step-by-step explanation:

A. N ( n − 2 ) ( n + 2 ) = n 3 − 4 n

We need to show that (left-hand-side)L.H.S = R.H.S (right-hand-side)

So,

 n ( n − 2 ) ( n + 2 ) = n(n² - 2²)     (difference of two squares)

                               = n³ - 2²n       (expanding the brackets)

                               = n³ - 4n         (simplifying)

So,                L.H.S  = R.H.S

B. ( x + 1 )² − 2x + y² = x² + y² + 1

We need to show that (left-hand-side)L.H.S = R.H.S (right-hand-side)

So,

( x + 1 )² − 2x + y² = x² + 2x + 1 - 2x + y²   (expanding the brackets)

                             = x² + 2x - 2x + 1  + y²   (collecting like terms)

                             = x² + 1 + y²        

                             = x² + y² + 1                    (re-arranging)

So,              L.H.S  = R.H.S

So, both A and B are true identities since we have been able to show that L.H.S  = R.H.S in both situations.

7 0
3 years ago
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