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irakobra [83]
3 years ago
12

Identify the lengths of AB and AC. HELP ASAP!!

Mathematics
1 answer:
Montano1993 [528]3 years ago
4 0

Answer:

Step-by-step explanation: AB = 28, and AC = 42

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olganol [36]

Answer

12

3/4=9/x

3x=9(4)

3x=36

x=36/3

x=12

7 0
3 years ago
(X^4-81)/x^3+3x^2+9x+27
Iteru [2.4K]

Answer:

x-3

Step-by-step explanation:

(x^2-9)(x^2-9)/x^2*(x+3)+9(x+3)

(x+3)*(x^2+9)/(x+3)*(x^2+9) cross multiply

(x^2+9)*(x+3)/(x^2+9) cross multiply

x+3 final anser

6 0
3 years ago
Solve for x in simplest form.<br>14 = 1/3(8x + 6)​
elena-s [515]

Answer:

x = 4.5

Step-by-step explanation:

14 = 8/3x + 2

12 = 8/3x

36 = 8x

x = 4.5

5 0
3 years ago
Which piecewise function is shown in the graph?
mash [69]

Based on the characteristics of <em>linear</em> and <em>piecewise</em> functions, the <em>piecewise</em> function f(x) = \left \{ {{-0.5\cdot x +1, \,x < 0} \atop {2\cdot x - 2, \,x \ge 0}} \right. is shown in the graph attached herein. (Correct choice: A)

<h3>How to determine a piecewise function</h3>

In this question we have a graph formed by two different <em>linear</em> functions. <em>Linear</em> functions are polynomials with grade 1 and which are described by the following formula:

y = m · x + b     (1)

Where:

  • x - Independent variable.
  • y - Dependent variable.
  • m - Slope
  • b - Intercept

By direct observation and by applying (1) we have the following <em>piecewise</em> function:

f(x) = \left \{ {{-0.5\cdot x +1, \,x < 0} \atop {2\cdot x - 2, \,x \ge 0}} \right.

Based on the characteristics of <em>linear</em> and <em>piecewise</em> functions, the <em>piecewise</em> function f(x) = \left \{ {{-0.5\cdot x +1, \,x < 0} \atop {2\cdot x - 2, \,x \ge 0}} \right. is shown in the graph attached herein. (Correct choice: A)

To learn more on piecewise functions: brainly.com/question/12561612

#SPJ1

3 0
2 years ago
120 books increased by 55%
Novay_Z [31]

<span> To find 55% of 120 books, multiply 120 x .55  
Then add that answer to the original 120.</span>

120 + 55% = 186

6 0
3 years ago
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