Help I need answers!! please

After I substitute in y how do I determine the coordinate(s)?

klasskru [66]

Simplifying both sides of the equation then isolating the variable

6 0

3 years ago

THIS is due in a hour Justin gave the waiter a $2.25 tip at the restaurant. If his meal cost $12.50, what percent tip did he giv

polet [3.4K]

2.25/12.50 = 0.18. then turn 0.18 into a percentage by doing 0.18 x 100 = 18%. Therefore, he gave an 18% tip.

3 0

3 years ago

Read 2 more answers

a carpet store has 4 commercials every hour on a local television station how many commercials will the store have in 233 hours?

LuckyWell [14K]

Answer:

932

Step-by-step explanation:

If they have 4 every hour, and there's 233 hours, you multiply 233 by 4.

3 0

3 years ago

Keith wants to save money to purchase a car. He buys an annuity with quarterly payments that earn 2.8% interest, compounded quar

lions [1.4K]

can you help me I'm doing a exam that ends in 7 min

Who must vote in favor of a bill that proposes statehood for a territory?

A. House of Representatives only

B. Senate only

C. House of Representatives and Senate

D. President of the United States

plssssssss help :(

8 0

3 years ago

The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the

gladu [14]

Answer:

Part 1) Australia $19,751,012\ people$

Part 2) China $1,319,645,764\ people$

Part 3) Mexico $109,712,539\ people$

Part 4) Zaire $60,534,681\ people$

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$P(t)=a(1+r)^t$

where

P(t) is the population

t is the number of years since year 2000

a is he initial value

r is the rate of change

Part 1) Australia

we have

$a=19,169,000\\r=0.6\%=0.6\100=0.006$

substitute

$P(t)=19,169,000(1+0.006)^t$

$P(t)=19,169,000(1.006)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=19,169,000(1.006)^5=19,751,012\ people$

Part 2) China

we have

$a=1,261,832,000\\r=0.9\%=0.9\100=0.009$

substitute

$P(t)=1,261,832,000(1+0.009)^t$

$P(t)=1,261,832,000(1.009)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people$

Part 3) Mexico

we have

$a=100,350,000\\r=1.8\%=1.8\100=0.018$

substitute

$P(t)=100,350,000(1+0.018)^t$

$P(t)=100,350,000(1.018)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=100,350,000(1.018)^5=109,712,539\ people$

Part 4) Zaire

we have

$a=51,965,000\\r=3.1\%=3.1\100=0.031$

substitute

$P(t)=51,965,000(1+0.031)^t$

$P(t)=51,965,000(1.031)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=51,965,000(1.031)^5=60,534,681\ people$

8 0

3 years ago