Answer:
5e⁵ˣ
Step-by-step explanation:
Use the implicit differentiation method
let 5x = a
da/dx = 5, da=5dx
y=eᵃ, dy/da=eᵃ
dy/dx=dy/da . da/dx
hence, dy/dx = 5e⁵ˣ
0.3
1/(5^12 * 32^3 * 9^15)
5^-12 = 1/(5^12)
32^-3 = 1/(32^3)
9^-15 = 1/(9^15)
1/(5^12) * 1/(32^3) * 1/(9^15) = 1/(5^12 * 32^3 * 9^15)
just plug in
g(x)=7x
g(-7)=7*(-7)
7*(-7)=-49
