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Luden [163]
3 years ago
8

The essay lengths of 29 randomly sampled essays are used to estimate the mean of the population. What t-score should be used to

find the 95% confidence interval for the population mean? g
Mathematics
1 answer:
slavikrds [6]3 years ago
5 0

Answer:

A t-score of 1.701 should be used to find the 95% confidence interval for the population mean

Step-by-step explanation:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 29 - 1 = 28

Now, we have to find a value of T, which is found looking at the t table, with 28 degrees of freedom(y-axis) and a confidence level of 0.95(t_{95}). So we have T = 1.701.

A t-score of 1.701 should be used to find the 95% confidence interval for the population mean

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pochemuha

Answer:

x = 79

Step-by-step explanation:

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2x + 32 = 180 subtract 32 from both sides

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Evaluate the difference quotient for the given function. Simplify your answer.
nasty-shy [4]

I suppose you mean

f(x) = \dfrac{x+5}{x+1}

Then

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and the difference quotient is

\dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5}{x+1}-2}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5-2(x+1)}{x+1}}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{-x+3}{(x+1)(x-3)} \\\\ \dfrac{f(x)-f(3)}{x-3} = \boxed{-\dfrac{x-3}{(x+1)(x-3)}}

If it's the case that <em>x</em> ≠ 3, then (<em>x</em> - 3)/(<em>x</em> - 3) reduces to 1, and you would be left with

\dfrac{f(x)-f(3)}{x-3}\bigg|_{x\neq3} = -\dfrac1{x+1}

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2 years ago
What is the value of x in this equation 3(2x-5)-4x=-11
GaryK [48]

Answer:

x=13

Step-by-step explanation:

6x-15-4x=11

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3 years ago
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