0.21jbvghhjjjjhhhyyhhhhhhjjjj
Call the number of trumpet players "T" and the number of horn players "H".
We can use the given information to set up equations:
1."<span>the number of trumpet players is 4 times the number of French horn players"

2. "</span><span>There are 35 trumpet and French horn players in the band."

If you were asked to solve you could now do it by substitution:






</span>
The shaded areas add to 2/5 of the area of the circle, which is given by
A = πr²
Then the shaded area is ...
(2/5)A = (2/5)π(10 in)²
shaded area = 40π in²
Answer:
The maximum volume of the open box is 24.26 cm³
Step-by-step explanation:
The volume of the box is given as
, where
and
.
Expand the function to obtain:

Differentiate wrt x to obtain:

To find the point where the maximum value occurs, we solve



Discard x=3.54 because it is not within the given domain.
Apply the second derivative test to confirm the maximum critical point.
, 
This means the maximum volume occurs at
.
Substitute
into
to get the maximum volume.

The maximum volume of the open box is 24.26 cm³
See attachment for graph.