<span>Average mass of a kernel of popcorn = 0.125 g
</span><span>1 pound = 16 ounces, and 1 ounce = 28.3 g
</span><span>how many kernels of popcorn are there in 0.500 pounds of popcorn = ?
0.500 pound = 16 x 0.500 ounces = 8 ounces
8 ounces = 8 x 28.3g = 226.4 g
Now divide this quantity by average mass;
226.4 / 0.125
= 811.2 kernels of popcorn</span>
The b stands for the y intercept ( where the graph cuts the y axis be sure to give me the brainliest answer
30 dollars profite hope this helps !!
Answer:
4446.72
Step-by-step explanation:
46% = 0.46
<em>46 % </em><em>of</em><em> the total</em> = 0.46 *x
<em>46% of the total</em> is 2045.49
0.46 *x = 2045.49
x = 2045.49 /0.46 ≈ 4446.71739 ≈ 4446.72
Complete question:
Consider 3 boxes, each of which contains 4 balls in particular, box 1 contains 4 white balls, box 2 contains 3 white balls and 1 red ball, box 3 contains 2 white balls and 2 red balls. Frank chooses a box at random. If boxes 1 and 3 are chosen, Frank extracts 2 balls without replacement. If box 2 is chosen Frank extracts 2 balls with replacement. USE ONLY THE CONDITIONAL PROBABILITY FORMALISM and derive an expression for the probability that the 2 extracted balls are red.
Answer:
11/288
Step-by-step explanation:
We are given:
Box 1: ( 4White, ORed)
Box 2: (3White, 1Red)
Box 3: (2White, 2 Red)
We are told that if Frank choose from Box 1 and Box 3, 2 balls are extracted without replacement.
Since there is no red ball in Box 1, there is no way 2 red balls will come out from Box1.
Our Event, E = getting 2 red balls.
Now Box 1 is ruled out, we have:
P[E(B1)]= 0
P[E/B3)] = (2 2) / (4 2)
= 1/6
If box 2 is chosen, 2 balls are extracted with replacement. Therefore for Box 2:
P(E/B2) = (1/4) *(1/4)
= 1/16
Therefore probability that 2 balls extracted are red, we have:
P(E)=P(E/B1) P(B1) + P(E/B2) P(B2)+P(E/B3) P(B3)
= 11/288