Answer:
0.9375
Step-by-step explanation:
Given the following :
Number of coin tosses = 7
Probability that number of heads obtained will be between 2 and 7 inclusive?
x = 2,3,4,5,6,7
Probability (P) = number of required outcomes / total possible outcomes
For a coin toss = 1 Head (H), 1 tail (T)
P(H) = 1 / 2
P(X) = C(7,x) * (1/2)^7
P(X) = C(7, x) / 0.5^-7
P(X) = [C(7,2) + C(7, 3)+ C(7,4) +C(7,5) + C(7,6) +C(7,7)] / 128
P(X) = (21 + 35 + 35 + 21 + 7 + 1) / 128
P(X) = 120 / 128
P(X) = 0.9375
When you go into this problem, you want to figure out your marble ammount to 50 so in this case we will say C for color and 50 for the total ammount of marbles.
We know 15 are pink, 8 are black, 2 are green, 18 are clear, and 7 are striped
15P/50
8B/50
2G/50
18C/50
7S/50 for a total of 50 marbles
Now we use the chart to decide our awnsers
A. We know our propability of drawing a green and clear is 20/50 which if we simplify is a 2/5 ratio. If We put this in perspective 2/5 is rare and is unlikley to even.
B. We know a striped marble is 18/50 or 1.8/5 ratio which is mainly unlikely
C. We have 23/50 marbles that are black and pink, our propability is about 2.3/5 and gives us an even chance to get one of these
D. We know we have 33/50 marbles that are pink and clear and gives us a 3.3/5 chance of getting one of these and gives us an even to likely chance of getting one of these.
E. If we have a total of 17 marbles in these 3 colors, we have a 1.7/5 chance of getting one of these and is probably impossible to unlikey.
Carlos is wrong since when subtracted 2175 from 1833 you get 342 so that's about one third of what he said.
Formula for trapezoid area is A=b1+b2 x heightx 1/2 so your answer would be 161m squared
