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umka2103 [35]
3 years ago
5

+54- -75 what the answer

Mathematics
2 answers:
Lostsunrise [7]3 years ago
3 0

Answer:

-21

Step-by-step explanation:

positive 54 decreased negative 75. The answer is -21. why? Because the negative variables is higher than the positive variable in the given.

notsponge [240]3 years ago
3 0

Answer:

129

Step-by-step explanation:

+54- -75

54+75=129

When you are subtracting 54- -75, the symbols will automatically change to postives.

You could also use the method:

Keep, change, change

54          +            +75

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HELP Find the value of x
emmasim [6.3K]
X=100
360-63= 297
297-80=217
217-100=117
117/3=39
4 0
3 years ago
Write 625 using exponents in as many ways as you can?
Arlecino [84]

Answer:

See below

Step-by-step explanation:

625 = 25^2, or (5^2)^2 = 5^4

8 0
3 years ago
Read 2 more answers
Elimination: 3x+4y=27; 5x-3y=16
aliya0001 [1]
The solution is:
y = 3
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7 0
3 years ago
How many strings can be formed by ordering the letters MISSISSIPPI which
Mazyrski [523]

Answer:

<em>1680 is the answer.</em>

Step-by-step explanation:

Here, we have 11 letters in the word <em>MISSISSIPPI.</em>

Repetition of letters:

M - 1 time

I - 4 times

S - 4 times

P - 2 times

As per question statement, we need a substring MISS in the resultant strings.

So, we need to treat MISS as one unit so that <em>MISS always comes together in all the strings</em>.

The resultant strings will look like:

<em>xxxxMISSxxx</em>

<em>xxMISSxxxxx</em>

<em>and so on.</em>

After we treat <em>MISS </em>as one unit, total letters = 8

Repetition of letters:

MISS - 1 time

I - 3 times

S - 2 times

P - 2 times

The formula for combination of letters with total of <em>n </em>letters:

\dfrac{n!}{p!q!r!}

where <em>p, q</em> and <em>r</em> are the number of times other letters are getting repeated.

<em>p = 3</em>

<em>q = 2</em>

<em>r = 2</em>

<em></em>

So, required number of strings that contain MISS as substring:

\dfrac{8!}{3!2!2!}\\\Rightarrow \dfrac{40320}{6\times 2 \times 2}\\\Rightarrow 1680

So, <em>1680 is the answer.</em>

3 0
3 years ago
Find a polynomial, which, when added to the polynomial 5x^2–3x–9, is equivalent to <br><br> x^2-5x+6
alexandr1967 [171]
So this is easy counting
so 5x^2-3x-9
we have 5 x^2's
-3 x's
-9

wat do we add to that to get
1 x^2's
-5 x's
+6
so we do each
5x^2+what=1x^2
subtract 5x^2
from both sides
what=-4x^2
first is -4x^2

then we have -3x to -5x
-3x+what=-5x
add 3x to both sides
what=-2x
second is -2x

-9 to 6
-9+ what=6
ad d9
what=15
last is 15
thereffor add -4x^2-2x+15

6 0
3 years ago
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