ANSWER:
12/25 = sinD*CosD
3/5 = SinD
16/15 = CosC*tanD
4/5 = tanC*tanD
STEP BY STEP EXPLANATION:
Finding the angles
Finding angle BCD
Sin(90)/5=Sin(BCD)/3
3sin(90)=5Sin(BCD)
3sin(90)/5=Sin(BCD)
sin^-1(3sin(90)/5) = /BCD
36.86989765 degrees = /C
Finding angle /CDB
Sin(90)/5=Sin(CDB)/4
Sin^-1(4sin(90)/5) = /CDB
53.13010235 degrees = /D
Evaluate the given question:
SinD=Sin(53.13010235)=0.8
SinC=Sin(38.86989765)=0.600000001
SinD*CosD = 0.48
TanC*TanD = 1
CosC*TanD = 1.066666666
FINAL EVALUATION
12/25 = 0.48
3/5 = 0.6
16/15 = 1.066666667
4/5 = 0.8
FINAL ANSWER
12/25 = SinD*CosD
3/5 = SinC
16/15 = CosC*TanD
4/5 = SinD
Hopefully it was useful :)
Answer:
The value of Tan (a + b) is .
Step-by-step explanation:
Given as :
Tan b =
Sin a =
∵Sin Ф =
So, =
Now, Base² = Hypotenuse² - Perpendicular²
Or, Base² = 13² - 12²
Or, Base² = 169 - 144
Or, Base² = 25
∴ Base = = 5
And Tan Ф =
Or, Tan a =
Now, Tan (a + b) =
Or, Tan (a + b) =
or, Tan (a + b) =
or, Tan (a + b) =
Or, Tan (a + b) =
Hence The value of Tan (a + b) is . Answer
Answer:
The results don't make sense
Step-by-step explanation:
We can solve by means of a 2x2 system of equations, we have to:
"x" is the number of children's tickets
"y" is the number of adult tickets
Thus:
8 * x + 8.75 * y = 259
x + y = 35 => x = 35 - y
replacing we have:
8 * (35 - y) + 8.75 * y = 259
280 - 8 * y + 8.75 * y = 259
- 8 * y + 8.75 * y = 259 - 280
0.75 * y = -21
y = -21 / 0.75
y = -28
Thus:
x = 35 - (-28) = 63
With these results we notice that the problem has inconsistency, since the value of the tickets cannot be given a negative number, I recommend reviewing the problem, since the approach is correct.
<span>More please help me solve the problem
The stars have different brightness. The brightest stars are Grade 1 and the least degree luimnoase stars 6. The brightness of the stars shrinks 2.5 times with the passing from one grade to another. Whenever the stars are brighter Grade 1, Grade 6 than the stars?</span>
Answer:
shift of 6 units left
Step-by-step explanation:
Given f(x) then f(x + a) is a horizontal translation of f(x)
• If a > 0 then a shift left of a units
• If a < 0 then a shift right of a units
f(x) = 3 | x + 6 | + 9
Represents a horizontal shift of the parent function 6 units left