How do I factor x ^5−x^ 4+3x−3

Please help!! circles combos are too hard

malfutka [58]

Answer:

56 + 53pi

Step-by-step explanation:

Area of small circles:

diameter of small circle: 4cm

forumla to find area of circle: A = pir^2

r is radius = half of diameter -> d/2 = 4 / 2 = 2cm

A = pi (2cm)^2

A = pi (4cm)

A = 4pi

Area of large circle:

diameter of small circle: 4cm

forumla to find area of circle: A = pir^2

r is radius = half of diameter -> d/2 = 14 / 2 = 7cm

A = pi (7cm)^2

A = pi (49cm)

A = 49pi

Area of rectangle:

Area = width x length

Area = 14cm x 4cm

Area = 56cm

Add all three areas:

Area of rectangle + large circle + small circle

56cm + 49pi + 4pi = 56cm + 53pi

7 0

2 years ago

Find the coefficient of variation for each of the two sets of data, then compare the variation. Round results to one decimal pla

svp [43]

Here is the correct computation of the question given.

Find the coefficient of variation for each of the two sets of data, then compare the variation. Round results to one decimal place. Listed below are the systolic blood pressures (in mm Hg) for a sample of men aged 20-29 and for a sample of men aged 60-69.

Men aged 20-29: 117 122 129 118 131 123

Men aged 60-69: 130 153 141 125 164 139

Group of answer choices

a)

Men aged 20-29: 4.8%

Men aged 60-69: 10.6%

There is substantially more variation in blood pressures of the men aged 60-69.

b)

Men aged 20-29: 4.4%

Men aged 60-69: 8.3%

There is substantially more variation in blood pressures of the men aged 60-69.

c)

Men aged 20-29: 4.6%

Men aged 60-69: 10.2 %

There is substantially more variation in blood pressures of the men aged 60-69.

d)

Men aged 20-29: 7.6%

Men aged 60-69: 4.7%

There is more variation in blood pressures of the men aged 20-29.

Answer:

(c)

Men aged 20-29: 4.6%

Men aged 60-69: 10.2 %

There is substantially more variation in blood pressures of the men aged 60-69.

Step-by-step explanation:

From the given question:

The coefficient of variation can be determined by the relation:

$coefficient \ of \ variation = \dfrac{standard \ deviation}{mean}*100$

We will need to determine the coefficient of variation both men age 20 - 29 and men age 60 -69

To start with;

The coefficient of men age 20 -29

Let's first find the mean and standard deviation before we can do that ;

SO .

Mean = $\dfrac{\sum \limits^{n}_{i-1}x_i}{n}$

Mean = $\frac{117+122+129+118+131+123}{6}$

Mean = $\dfrac{740}{6}$

Mean = 123.33

Standard deviation $= \sqrt{\dfrac{\sum (x_i- \bar x)^2}{(n-1)} }$

Standard deviation = $\sqrt{\dfrac{(117-123.33)^2+(122-123.33)^2+...+(123-123.33)^2}{(6-1)} }$

Standard deviation = $\sqrt{\dfrac{161.3334}{5}}$

Standard deviation = $\sqrt{32.2667}$

Standard deviation = 5.68

The $coefficient \ of \ variation = \dfrac{standard \ deviation}{mean}*100$

$coefficient \ of \ variation = \dfrac{5.68}{123.33}*100$

Coefficient of variation = 4.6% for men age 20 -29

For men age 60-69 now;

Mean = $\dfrac{\sum \limits^{n}_{i-1}x_i}{n}$

Mean = $\frac{ 130 + 153 + 141 + 125 + 164 + 139}{6}$

Mean = $\dfrac{852}{6}$

Mean = 142

Standard deviation $= \sqrt{\dfrac{\sum (x_i- \bar x)^2}{(n-1)} }$

Standard deviation = $\sqrt{\dfrac{(130-142)^2+(153-142)^2+...+(139-142)^2}{(6-1)} }$

Standard deviation = $\sqrt{\dfrac{1048}{5}}$

Standard deviation = $\sqrt{209.6}$

Standard deviation = 14.48

The $coefficient \ of \ variation = \dfrac{standard \ deviation}{mean}*100$

$coefficient \ of \ variation = \dfrac{14.48}{142}*100$

Coefficient of variation = 10.2% for men age 60 - 69

Thus; Option C is correct.

Men aged 20-29: 4.6%

Men aged 60-69: 10.2 %

There is substantially more variation in blood pressures of the men aged 60-69.

4 0

3 years ago

Write the formula of the function y whose graph is show.

elena-14-01-66 [18.8K]

Answer:

im on the same question

7 0

3 years ago

If p base and b is the perpendicular of a right triangle find the area of a triangle

Likurg_2 [28]

Answer:

Area of triangle= Half of perpendicular times base

In short:1/2×p×b

7 0

2 years ago

If the point (2, 5) is a solution to the system of equations shown below, then determine the missing values of b and m. Show how

antoniya [11.8K]

Complete Question:

If the point (2, 5) is a solution to the system of equations shown below, then determine the missing values of b and m. Show how you arrive at your answer.

1. y = 3x + b

2. y = mx + 9

Answer:

1. Intercept, b = -1

2. Slope, m = -2

Step-by-step explanation:

Given the following data;

Points on the line (x, y) = (2, 5)

To find the missing values;

Mathematically, the equation of a straight line is given by the formula;

y = mx + b

Where;

m is the slope.
x and y are the points
b is the intercept.

1. y = 3x + b

Substituting the value of x and y, we have;

5 = 3(2) + b

5 = 6 + b

b = 5 - 6

Intercept, b = -1

2. y = mx + 9

Substituting the value of x and y, we have;

5 = m(2) + 9

5 = 2m + 9

2m = 5 - 9

2m = -4

m = -4/2

Slope, m = -2

6 0

3 years ago