Answer:
The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.
Step-by-step explanation:
According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.
Then, the mean of the distribution of sample mean is given by,

And the standard deviation of the distribution of sample mean is given by,

The information provided is:
<em>μ</em> = 144 mm
<em>σ</em> = 7 mm
<em>n</em> = 50.
Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:


*Use a <em>z</em>-table for the probability.
Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.
<h3>
Answer: Choice C</h3>
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Work Shown:
Reference angle = P
Opposite side = QR = 8.5
Adjacent side = QP = 16
tan(angle) = opposite/adjacent
tan(P) = QR/QP
tan(P) = 8.5/16
tan(P) = 0.53125
tan(P) = 0.53
The glass part of the frame is an illustration of fractions
The width of each side of the frame is 5 1/4 inches
<h3>How to determine the width of each side?</h3>
The given parameters are:
- Total width = 42 inches
- Glass part = 32 1/2 inches
Represent the width of each side with x.
So, we have:
Glass part + 2x = Total width
Substitute known values
31 1/2 + 2x = 42
Subtract 31 1/2 from both sides
2x = 10 1/2
Divide both sides by 2
x = 5 1/4
Hence, the width of each side of the frame is 5 1/4 inches
Read more about fractions at:
brainly.com/question/1622425
It would be C because using the methof of rise over run, the change in x is 6 while the change in y is 17. So 14/6 woll get you 7/3.