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ella [17]
4 years ago
8

How can you tell if radicals are like radicals?

Mathematics
1 answer:
Natasha_Volkova [10]4 years ago
3 0
Like radicals<span> are the radicals that have the same index. The numbers which lie in the same root or those numbers whose power are same are called like radicals.</span>
You might be interested in
How to find area? will give..
ch4aika [34]

Answer:

Step-by-step explanation:

A=πr2

Circumference = 2πr

20π = 2πr

r=10

π=3.14

A=3.14 * 10^2

=314 cm^2

3 0
3 years ago
Anthony has to practice his guitar for 1.75 hours each morning and 2.5 hours each evening for the first 4 days this week. How ma
weqwewe [10]

Answer:

17 hours

Step-by-step explanation:

From the above question,

Anthony is practicing 4 days in a week

Hence

The number of hours he practices in the morning for 4 days =

1.75 hours × 4

= 7 hours

The number of hours he practices in the evening for 4 days =

2.5 hours × 4

= 10 hours

Therefore, the total number of hours he practices this week

= 7 hours + 10 hours

= 17 hours

5 0
3 years ago
How to solve 37=-3+5(x+6)
zavuch27 [327]
Distribute Property 5(x+6) basically means 5×x + 5×6 = 5x+30

37= -3+5x+30 (subtract 30 on both sides)

7=-3+5x (add three on both sides)

10= 5x (divide 5 on both sides)

x=2 
7 0
3 years ago
Having trouble w graphing :(
NISA [10]

6x/6=x>/= (=) 11/6

x=11/6 or about 1.8

the first important notation to remember when graphing inequalities is that the graph is going to face the way the inequality sign is pointing.

in this case, the sign is pointing right. now the second thing to remember is that an inequality sign with a line underneath it means that it is greater/equal to so the graph in which we fill will have be a closed circle

1) start the ray at ~1.8 and fill in the circle at the end of the ray then extend to its endpoint

that's all. you're graph now reads  x is greater or equal to 11/6

3 0
3 years ago
3(s-5)/4 -3 = 4s- (s-3)/2<br>pls answer fast​
Jobisdone [24]

Answer:

s =  \frac{9± \sqrt{ - 39} }{4}

Step-by-step explanation:

\frac{3(s - 5)}{4 - 3}  =  \frac{4s \times (s - 3)}{2}

➡️ \frac{3(s - 5)}{1}  = 2s \times (s - 3)

➡️ 3s - 15 = 2 {s}^{2}  - 6s

➡️ 3s - 15  -  2 {s}^{2}  + 6s = 0

➡️ 9s - 15 - 2 {s}^{2}  = 0

➡️ - 2 {s}^{2}  + 9s - 15 = 0

➡️ 2 {s}^{2}  - 9s + 15 = 0

➡️ s =  \frac{ - ( - 9)± \sqrt{( - 9 {)}^{2}  - 4 \times 2 \times 15} }{2 \times 2}

➡️ s =  \frac{9± \sqrt{81 - 120} }{4}

➡️ s =  \frac{9± \sqrt{ - 39} }{4}

➡️ s∉ℝ

5 0
3 years ago
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