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2 years ago

What is the vertex of the function?

Mathematics

2 answers:

zheka24 [161]2 years ago

6 0

Answer:

(4 , -25)

Step-by-step explanation:

that is the procedure above

katrin [286]2 years ago

3 0

the vertex of the parabola is calculated by the formula

$\displaystyle\ ax^2+bx+c\quad ;\quad \boxed{x_0=\frac{-b}{2a} \ \ ;\quad y_0 =ax_0^2+bx_0+c} \\\\x_0=-\frac{-8}{2} =4 \quad ; \ \ y_0 =16-32-9=-25 \\\\\ \ Answer: Coordinates \ \ of \ the \ vertex \ of \ the \ \ parabola \ \ (4;-25)$

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Stephan added 26 new contacts to his phone list. He had to delete 16 old contacts before he could add any more. Stefan now has a

bezimeni [28]

Answer: 26-16= c

c=10

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a norm

Artemon [7]

Answer:

a) 0.5.

b) 0.8413

c) 0.8413

d) 0.6826

e) 0.9332

f) 1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 6, \sigma = 0.2$

(a) P(x > 6) =

This is 1 subtracted by the pvalue of Z when X = 6. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6-6}{0.2}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5.

1 - 0.5 = 0.5.

(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X 5.8.

X = 6.2

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

X = 5.8

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.8-6}{0.2}$