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julia-pushkina [17]
3 years ago
15

Please someone help asap.​

Mathematics
2 answers:
Orlov [11]3 years ago
8 0
I believe it’s C and A
Bogdan [553]3 years ago
4 0
I think the answers are A and C. For sure not D
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Step-by-step explanation:

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If a dilated images length is 9 and the width is 8, and the perimeter of the original image is 136 inches? what is the area of t
Greeley [361]

Answer:

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Step-by-step explanation:

7 0
3 years ago
If f(x) = -5^x -4 and g(x)= -3x-2 find (f+g)(x)
Citrus2011 [14]

Answer:

-5^x-3x-6

Step-by-step explanation:

7 0
3 years ago
A rectangular box is to have a square base and a volume of 40 ft3. If the material for the base costs $0.34 per square foot, the
MArishka [77]

Answer:

The dimensions of the box so that total costs are minimum are a side length of 2 feet and a height of 5 feet.

Step-by-step explanation:

Geometrically speaking, the volume of the rectangular box (V), in cubic feet, is represented by this formula:

V = l^{2}\cdot h (1)

Where:

l - Side length of the box, in feet.

h - Height of the box, in feet.

In addition, the total cost of the box (C), in monetary units, is defined by this formula:

C = (c_{b}+c_{t})\cdot l^{2} + 4\cdot c_{s}\cdot l\cdot h (2)

Where:

c_{b} - Unit cost of the base of the box, in monetary units per square foot.

c_{t} - Unit cost of the top of the box, in monetary units per square foot.

c_{s} - Unit cost of the side of the box, in monetary units per square foot.

By (1), we clear h into the expression:

h = \frac{V}{l^{2}}

And we expand (2) and simplify the resulting expression:

C = (c_{b}+c_{t})\cdot l^{2}+4\cdot c_{s}\cdot \left(\frac{V}{l} \right) (3)

If we know that c_{b} = 0.34\,\frac{m.u.}{ft^{2}}, c_{s} = 0.05\,\frac{m.u.}{ft^{2}}, c_{t} = 0.16\,\frac{m.u.}{ft^{2}} and V = 40\,ft^{3}, then we have the resulting expression and find the critical values associated with the side length of the base:

C = 0.5\cdot l^{2} + \frac{8}{l}

The first and second derivatives of this expression are, respectively:

C' = l -\frac{8}{l^{2}} (4)

C'' = 1 + \frac{16}{l^{3}} (5)

After equalizing (4) to zero, we solve for l: (First Derivative Test)

l-\frac{8}{l^{2}} = 0

l^{3}-8 = 0

l = 2\,ft

Then, we evaluate (5) at the value calculated above: (Second Derivative Test)

C'' = 3

Which means that critical value is associated with minimum possible total costs. By (1) we have the height of the box:

h = 5\,ft

The dimensions of the box so that total costs are minimum are a side length of 2 feet and a height of 5 feet.

8 0
3 years ago
‼️help please ASAP ‼️
Semmy [17]
You'll use the sine trig function because we want to tie together the known opposite side (10) and the unknown hypotenuse (x). 

sin(angle) = opposite/hypotenuse
sin(55) = 10/x
x*sin(55) = 10
x = 10/sin(55)
x = 12.2077 ... make sure your calculator is in degree mode
x = 12.2

Answer: Choice A
6 0
4 years ago
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