Zach found a rat snake in the woods near his home. Its length is 1.473 meters.
1 answer:
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Answer:
a) 30.726m/s and b) 5.5549s
Step-by-step explanation:
a.) What was Chris Huber’s speed in meters per second(m/s)?
Given the distance and time, the formula to obtain the speed is
.
Applying this to our problem we have that
.
So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.
b) What was Whittingham’s time through the 200 m?
In a) we stated that . This formula implies that
.
First, observer that .
Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So,
Then, applying 1) we have that
So, Sam Whittingham’s time through the 200 m was 5.5549s.
Answer:
The % growth rate is 15.8%.
Step-by-step explanation:
Let the function is given by , where f(w) is the number of a specific product produced after w weeks.
Now, given for w = 0, f(0) = 190 = a
So, the function becomes ............. (1)
Now, it is also give that at w = 1, f(1) = 220.
So, from equation (1) we get,
⇒ b = 1.15789.
Now, b = 1 + r
⇒ 1.15789 = 1 + r
⇒ r = 0.15789
Therefore, the % growth rate is 0.15789 × 100% = 15.8% (Approx.)