Zach found a rat snake in the woods near his home. Its length is 1.473 meters.

Write 169=13^2 in logarithmic form

e-lub [12.9K]

Answer:

$\log_{13}(169)=2$

Step-by-step explanation:

The given exponential form is:

$169=13^2$

The base of the given expression on the right is 13 and the exponent is 2.

The number is 169.

In terms of logarithms, the base still remains the base and the exponent becomes the result of the logarithm of the number 169 to the given base 13.

$\log_{13}(169)=2$

4 0

3 years ago

Can someone please answer. There is a picture. There is only one question. Thank you so much

Sloan [31]

So than you check this graph so you see that the radius has a length of 4 units
from what result that thet x^2 +y^2 =4

so the choice 3rd is right sure

3 0

3 years ago

Susie has a bag of marbles containing 3 Red, 7 Green, and 10 Blue marbles.

morpeh [17]

Answer:

1) a) 0.0945

b) 0.1062

2) a) 0.0138

b) 0.00081

3) a) 0.00094

b) 0.00083

4) 301.68 cents

5) 0.0056

Step-by-step explanation:

Since there are 3 Red, 7 Green, and 10 Blue marbles.

Total number of marbles N = 20

Probability (Red) = 3/20

Probability (Green) = 7/20

Probability (Blue) = 10/20

1) the probability of picking 5 marbles and getting at least one red marble

A) with replacement

P(at least 1 red of 5)= (3/20 * 17/20 * 17/20 * 17/20 * 17/20) + (3/20 * 3/20 * 17/20 * 17/20 * 17/20) + (3/20 * 3/20 * 3/20 * 17/20 * 17/20)

P(at least 1 red of 5) = 0.0783 +0.0138 + 0.0024 = 0.0945

B) without replacement

P(at least 1 red of 5) = ( 3/20 * 17/19* 16/18 * 15/17 * 14/16) + (3/20 * 2/19 * 17/18 * 16/17 * 15/16) + (3/20 * 2/19 * 1/18 * 17/17 * 16/16)

P(at least 1 red of 5) = 0.0921 + 0.01316 + 0.0009 = 0.1062

2) the probability of picking 6 marbles having 2 of each color

A) with replacement

P( 6, 2 of each) = 3/20 * 3/20 * 7/20 * 7/20 * 10/20 * 10/20

P( 6, 2 of each) = 0.0138

B) without replacement

P( 6, 2 of each) = 3/20 * 2/19 * 7/18 * 6/17 * 10/16 * 9/15

P( 6, 2 of each) = 0.00081

3) Pick 8 marbles: 4 green and 4 blue

A) with replacement

P(8, 4G and 4 B) = 7/20*7/20*7/20*7/20*10/20*10/20*10/20

P(8, 4G and 4 B) = 0.00094

B) without replacement

P(8, 4G and 4 B) = 7/20*6/19*5/18*4/17*10/16*9/15*8/14*7/13 = 0.00083

4) getting at least 6 marbles of the same color

Only Green and Blue marbles are more than 6

P(at least 6 marbles of the same color) = (7/20*6/19*5/18*4/17*3/16*2/15) + (10/20*9/19*8/18*7/17*6/16*5/15)

= 0.00018 + 0.00542

P(at least 6 marbles of the same color) = 0.0056

Cost of 6 .marbles= 6* 50 cents

C = 300 cents

Therefore, You will have to pay

(1 + 0.0056) 300 cent = 301.68 cents to be sure of getting at least 6 marbles of the same color

5) getting at least 6 marbles of the same color

Only Green and Blue marbles are more than 6

P(at least 6 marbles of the same color) = (7/20*6/19*5/18*4/17*3/16*2/15) + (10/20*9/19*8/18*7/17*6/16*5/15)

= 0.00018 + 0.00542

P(at least 6 marbles of the same color) = 0.0056

6 0

3 years ago

Fernando bought a jacket for 185 and sold it for 1 1/2 what he paid. Marisol spent 1/5 as much as Fernando on the same jacket bu

avanturin [10]

Answer:

Marisol made $138.75 on the sale of the jacket

Step-by-step explanation:

First we are told that Fernando bought a jacket for $185, and sold it for 1 1/12 what he paid.

Therefore, 1 1/2 of 185;

= 1.5 × 185 = $277.5

Therefore, Fernando sold the Jacket for $277.5

Next, we are told that:

Marisol spent 1/5 as much as Fernando on the same jacket

This means that Marisol spent 1/5 of $185 on the jacket

= 1/5 × 185 = 0.2 × 185 = $37

Therefore, Marisol spent $37 to buy the same jacket

Next, Marisol sold the jacket for 1/2 as much as Fernando. Since Fernando sold the Jacket for $277.5, Marisol sold the jacket for 1/2 of 277.5, and this is calculated as:

1/2 of 277.5 = 0.5 × 277.5 = 138.75

Therefore, Marisol made $138.75 on the sale of the jacket.

6 0

3 years ago

A large university accepts 60% of the students who apply. Of the students the university accepts, 40% actually enroll. If 30,

kykrilka [37]

Answer:

7,200

Step-by-step explanation:

Let's start by calculating how many students the university accepts. The problem says they accept 60% of the students. 60% as a decimal is 0.6. To calculate 60% of something, you multiply .60 by whatever quantity. In this case, it would be the students.

Number of accepted students = $.6 * 30000$ = 18,000

The university accepts 18,000 students.

Now, the next problem is that of those accepted students, we need to find out how many actually enroll. The problem says they accept 40% of the accepted students. Applying the same principle,

Number of enrolled students = $.4 * 18000$ = 7,200

The number of students that actually enroll is 7,200.

Alternatively, $.6 * 30000 * .4$ would give you the same result.

Combining the pieces together, we are asking for 60% of 30,000. Then getting 40% of that 60%.

3 0

3 years ago