For part A: the constant is 83.50. the variable would be c and w. and the coefficient would be 10c or 15w.
part B: so 10(4)+15(15)+83.50 -----> 10x4= 40------> 40+15(15)+83.50---->15x15=225
40+225+83.50=348.50
part C The coefficient would change because a constant is always constant, a variable is just a letter standing in for a number which would make the coefficient the one that changes for $10 to $20.
hope that help!
X-2 for x=-3
-3-2=-5, add dem negatives
Answer:
0^6= 1000000. The final answer is 25000000.
Answer:
2.Matrices and Linear Algebra. 2.1 Basics. Definition 2.1.1. A matrix is an m × n array ... aij = 0 i = j. (1b) A diagonal matrix A may be denoted by diag(d1,d2,... ,dn) ... space of A. With r1 (A),...,rm (A) denoting the rows of A the row space
4.Introduces reflections in the x- and y-axes. Demonstrates the ... This leaves us with the transformation for doing a reflection in the y-axis. For this transformation, I'll switch ... Many textbooks don't get any further than this. If these are all the rules ...
