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Agata [3.3K]
3 years ago
13

If you were born in 1925 how old are you in 1967

Mathematics
1 answer:
motikmotik3 years ago
7 0
If you were born in 1925 you would be 42 years old in 1967

1967 - 1925 = 42 
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By creating 2 new numbers what is the smallest possible sum that can be made
Tatiana [17]

Answer:

10 ??

Step-by-step explanation:

6 0
3 years ago
Which of the following equations is the inverse of the function f(x)=4x-7/9
Dmitry [639]

Answer:

f^-1(x)=7/36+x/4

Step-by-step explanation:


4 0
4 years ago
Find the exact value of cot 330° in simplest form with a rational denominator.
Hoochie [10]

Answer:

\cot 330^{\circ} = -\sqrt{3}

Step-by-step explanation:

The cotangent function can be rewritten by trigonometric relations, that is:

\cot 330^{\circ} = \frac{1}{\tan 330^{\circ}} = \frac{\cos 330^{\circ}}{\sin 330^{\circ}} (1)

By taking approach the periodicity properties of the cosine and sine function (both functions have a period of 360°), we use the following equivalencies:

\sin 330^{\circ} = \sin (-30^{\circ}) = -\sin 30^{\circ} (2)

\cos 330^{\circ} = \cos (-30^{\circ}) = \cos 30^{\circ} (3)

By (2) and (3) in (1), we have following expression:

\cot 330^{\circ} = -\frac{\cos 30^{\circ}}{\sin 30^{\circ}}

If we know that \sin 30^{\circ} = \frac{1}{2} and \cos 30^{\circ} = \frac{\sqrt{3}}{2}, then the result of the trigonometric expression is:

\cot 330^{\circ} = -\frac{\frac{\sqrt{3}}{2} }{\frac{1}{2} }

\cot 330^{\circ} = -\sqrt{3}

6 0
3 years ago
Determine the x- and the y-intercepts of these graphs. a) y = x-2​
Ivanshal [37]

Answer:

y-intercept = (0, -2)

x-intercept = (2, 0)

Step-by-step explanation:

The y-intercept is the value of y when x = 0. Therefore, Given the linear equation, y = x - 2:

Let x = 0:

y = 0 - 2

y = -2.

Therefore, the y-intercept of the linear equation, y = x - 2  is (0, -2).

The x-intercept is the value of x when y = 0.

Therefore, let y = 0:

y = x - 2

0 = x - 2

Isolate x by adding 2 to both sides of the equation:

0 + 2 = x - 2 + 2

2 = x

Therefore, the x-intercept is (2, 0).

5 0
3 years ago
If f(x) = –2x3, g(x) = 3x – 5, and h(x) = x – 1, what is f(g(h(3)))?<br> –129<br> –54<br> –53<br> –2
sineoko [7]

Answer:

f(x)  =  - 2 {x}^{3}  \\ g(x) = 3x - 5 \\ h(x) = x - 1 \\ g(h(x)) = 3(x - 1) - 5 \\  = 3x - 3 - 5 = 3x - 8 \\ f(g(h(x)) )= - 2 {(3x - 8)}^{3}  \\ f(g(h(3)) )=- 2 {(3(3) - 8)}^{3} \\  =  - 2 {(9 - 8)}^{3}  \\ f(g(h(3)) )=- 2

5 0
2 years ago
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