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DENIUS [597]
3 years ago
12

Two angles and a non included side of one triangle must be congruent to two angles and the corresponding non included side of th

e other triangle. Which method of congruence is this?
Mathematics
2 answers:
nalin [4]3 years ago
7 0

Answer:

See below.

Step-by-step explanation:

In the UK is called Congruence by 2 angles and a corresponding side.  In the USA it goes by the acronym AAS.

Ymorist [56]3 years ago
4 0

Answer: AAS theorem

Step-by-step explanation:

We know that the AAS (angle-angle-side) theorem says that when two angles and any side of a triangle are congruent to two angles and any side of other triangle, then the triangles are said to be congruent.

Since the theorem is applicable for any pair of congruent angles<em> either included or non - included.</em>

Therefore, the given statement "Two angles and a non included side of one triangle must be congruent to two angles and the corresponding non included side of the other triangle. "  represents AAS theorem of congruence.

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likoan [24]

Answer:  2^2 x 3^2 x 5

You can use a star symbol * in place of the x symbols.

==================================================

Explanation:

We simply circle the primes where they have the largest exponent.

The unique primes listed here are: 2, 3, 5

  • The prime 2 has the highest exponent of 2, meaning 2^2 is part of the answer.
  • The prime 3 has the highest exponent of 2, meaning 3^2 is also part of the LCM
  • The prime 5, without any exponent, is also part of the LCM. We can write this as 5^1 or just leave it as 5.
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3 years ago
First verify that y(x)y(x) satisfies the given differential equation. Then determine a value of the constant CC so that y(x)y(x)
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Answer:

at constant C = -56 satisfies the given condition of y(x)

Step-by-step explanation:

differentiate y(x) w.r.t.x

y' (x ) = \frac{d}{dx} (\frac{1}{4} x^5 +Cx^{-3} )

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        = \frac{5}{4} x^4 - 3Cx^{-4}

attached is the remaining part of the detailed solution and the sketch of the several typical solutions

6 0
3 years ago
A long distance runner starts at the beginning of a trail and runs at a rate of 4 miles per hour. two hours later, a cyclist sta
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To solve this problem, let us first assign variables. Let us say that:

A = runner

B = cyclist

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v = velocity

time = t

 

The time in which the cyclist overtakes the runner is the time wherein the distance of the two is the same, that is:

dA = dB

 

We know that the formula for calculating distance is:

d = v t

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vA tA = vB tB

 

Further, we know that tA = tB + 2, therefore:

vA (tB + 2) = vB tB

4 (tB + 2) = 14 tB

4 tB + 8 = 14 tB

10 tB = 8

tB = 0.8 hours = 48 min

 

Therefore the cyclist overtakes the runner after 0.8 hours or 48 minutes.

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Answer:

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Step-by-step explanation:

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