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kvv77 [185]
3 years ago
6

A long distance runner starts at the beginning of a trail and runs at a rate of 4 miles per hour. two hours later, a cyclist sta

rts at the beginning of the trail and travels at a rate of 14 miles per hour. what is the amount of time that the cyclist travels before overtaking the runner?
Mathematics
1 answer:
valina [46]3 years ago
8 0

To solve this problem, let us first assign variables. Let us say that:

A = runner

B = cyclist

d = distance

v = velocity

time = t

 

The time in which the cyclist overtakes the runner is the time wherein the distance of the two is the same, that is:

dA = dB

 

We know that the formula for calculating distance is:

d = v t

therefore,

vA tA = vB tB

 

Further, we know that tA = tB + 2, therefore:

vA (tB + 2) = vB tB

4 (tB + 2) = 14 tB

4 tB + 8 = 14 tB

10 tB = 8

tB = 0.8 hours = 48 min

 

Therefore the cyclist overtakes the runner after 0.8 hours or 48 minutes.

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Step-by-step explanation:

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Suppose you had to find 4 x 57. How are the expanded algorithm and the standard algorithm alike? And how are they different?
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4 0
3 years ago
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forsale [732]

Answer:

1.)    13\frac{3}{10}\\

2.)11\frac{3}{4}\\

3.)11\\

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5.)7\frac{11}{15}

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Step-by-step explanation:

I did 6 problems for you. You can now do the other 4 problems and see how I did it. You need to have the same denominator and the add the fractions together.

4 0
3 years ago
A rectangle has a perimeter of 18 cm.its length is 5 cm greater than its width.find the dimensions.
Marat540 [252]
P=18
l=5 cm greater than the width
w=5 less than the length

USE YOUR NUMBER SENSE!!! - just plug in different number below 4 to figure out the width

3=w  3+5=8 8+8=16+6=22    WILL NOT WORK

2=w   2+5=7  7+7=14   14+2+2= 18    WE HAVE A WINNER!!!!

FInal Answer: width: 2 cm and length: 7 cm
                          


5 0
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