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zhannawk [14.2K]

4 years ago

8

Suppose you earn 7.25 per hour working part time for a florist. Write and solve an inequality to find how many full hours you mu

st work to earn at least 125$

2 answers:

Mnenie [13.5K]4 years ago

7 0

17-18 !!!!!!!!!!!!!!!!

tiny-mole [99]4 years ago

5 0

17-18 hours i hope i helped

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A teacher wants to know whether the students in the entire school prefer watching television or playing outdoor games after scho

cupoosta [38]

D. All students in each grade. It can't be A since the survey is for the students, it defeats the purpose. It can't be B and C since those are too biased. Basing the student population on one factor like gender and sports is not logical in the context of this survey.

6 0

3 years ago

Read 2 more answers

Can someone solve 6÷2(1+2)

mamaluj [8]

Answer: 9

Step-by-step explanation:

To solve this problem, we need to use our order of operations, or PEMDAS.

Parenthesis

Exponent

Multiply

Divide

Add

Subtract

6÷2(1+2) [parenthesis]

6÷2(3) [multiply/divide from left to right]

3(3) [multiply]

9

Now, we know that the answer is 9.

8 0

3 years ago

Use the given information to find (a) sin(s+t), (b) tan(s+t), and (c) the quadrant of s+t. cos s = - 12/13 and sin t = 4/5, s an

Anton [14]

Answer:

Part a) $sin(s + t) =-\frac{63}{65}$

Part b) $tan(s + t) = -\frac{63}{16}$

Part c) (s+t) lie on Quadrant IV

Step-by-step explanation:

[Part a) Find sin(s+t)

we know that

$sin(s + t) = sin(s) cos(t) + sin(t)cos(s)$

step 1

Find sin(s)

$sin^{2}(s)+cos^{2}(s)=1$

we have

$cos(s)=-\frac{12}{13}$

substitute

$sin^{2}(s)+(-\frac{12}{13})^{2}=1$

$sin^{2}(s)+(\frac{144}{169})=1$

$sin^{2}(s)=1-(\frac{144}{169})$

$sin^{2}(s)=(\frac{25}{169})$

$sin(s)=\frac{5}{13}$ ---> is positive because s lie on II Quadrant

step 2

Find cos(t)

$sin^{2}(t)+cos^{2}(t)=1$

we have

$sin(t)=\frac{4}{5}$

substitute

$(\frac{4}{5})^{2}+cos^{2}(t)=1$

$(\frac{16}{25})+cos^{2}(t)=1$

$cos^{2}(t)=1-(\frac{16}{25})$

$cos^{2}(t)=\frac{9}{25}$

$cos(t)=-\frac{3}{5}$ is negative because t lie on II Quadrant

step 3

Find sin(s+t)

$sin(s + t) = sin(s) cos(t) + sin(t)cos(s)$

we have

$sin(s)=\frac{5}{13}$

$cos(t)=-\frac{3}{5}$

$sin(t)=\frac{4}{5}$

$cos(s)=-\frac{12}{13}$

substitute the values

$sin(s + t) = (\frac{5}{13})(-\frac{3}{5}) + (\frac{4}{5})(-\frac{12}{13})$

$sin(s + t) = -(\frac{15}{65}) -(\frac{48}{65})$

$sin(s + t) =-\frac{63}{65}$

Part b) Find tan(s+t)

we know that

tex]tan(s + t) = (tan(s) + tan(t))/(1 - tan(s)tan(t))[/tex]

we have

$sin(s)=\frac{5}{13}$

$cos(t)=-\frac{3}{5}$

$sin(t)=\frac{4}{5}$

$cos(s)=-\frac{12}{13}$

step 1

Find tan(s)

$tan(s)=sin(s)/cos(s)$

substitute

$tan(s)=(\frac{5}{13})/(-\frac{12}{13})=-\frac{5}{12}$

step 2

Find tan(t)

$tan(t)=sin(t)/cos(t)$

substitute

$tan(t)=(\frac{4}{5})/(-\frac{3}{5})=-\frac{4}{3}$

step 3

Find tan(s+t)

$tan(s + t) = (tan(s) + tan(t))/(1 - tan(s)tan(t))$

substitute the values

$tan(s + t) = (-\frac{5}{12} -\frac{4}{3})/(1 - (-\frac{5}{12})(-\frac{4}{3}))$

$tan(s + t) = (-\frac{21}{12})/(1 - \frac{20}{36})$

$tan(s + t) = (-\frac{21}{12})/(\frac{16}{36})$

$tan(s + t) = -\frac{63}{16}$

Part c) Quadrant of s+t

we know that

$sin(s + t) =negative$ ----> (s+t) could be in III or IV quadrant

$tan(s + t) =negative$ ----> (s+t) could be in III or IV quadrant

Find the value of cos(s+t)

$cos(s+t) = cos(s) cos(t) -sin (s) sin(t)$

we have

$sin(s)=\frac{5}{13}$

$cos(t)=-\frac{3}{5}$

$sin(t)=\frac{4}{5}$

$cos(s)=-\frac{12}{13}$

substitute

$cos(s+t) = (-\frac{12}{13})(-\frac{3}{5})-(\frac{5}{13})(\frac{4}{5})$

$cos(s+t) = (\frac{36}{65})-(\frac{20}{65})$

$cos(s+t) =\frac{16}{65}$

we have that

$cos(s+t)=positive$ -----> (s+t) could be in I or IV quadrant

$sin(s + t) =negative$ ----> (s+t) could be in III or IV quadrant

$tan(s + t) =negative$ ----> (s+t) could be in III or IV quadrant

therefore

(s+t) lie on Quadrant IV

4 0

3 years ago

Determine the Vertex of the following absolute value function.

prisoha [69]

Answer:

vertex = (-4, 5)

Step-by-step explanation:

In general, the graph of the absolute value function f(x) = a|x - h| + k will have its lowest value when f(x) = k (or highest value for f(x) = -a|x - h| + k). The lowest/highest value is the vertex (turning point).

Therefore, from inspection of the equation we can say that the y-coordinate of the vertex is 5.

Set the equation to 5 and then solve for x:

⇒ 5 = 1/2 |-X – 4| + 5

⇒ 1/2 |-X – 4| = 0

⇒ |-X – 4| = 0

Therefore, (-X - 4) = 0 and -(-X - 4) = 0

⇒ X = -4 (for both)

So the vertex is (-4, 5)

<u>Translations</u>

Absolute value parent function: f(x) = | -x |

Horizontal translation left 4 units: f(x) = |-x - 4|

Horizontal stretch of sf 1/2: f(x) = 1/2 |-x - 4|

Vertical translation up 5 units: f(x) = 1/2 |-x - 4| + 5

6 0

3 years ago

Andrea has a jug containing 1.5 liters of chocolate milk. She fills one cup with 250 milliliters and another cup with 0.6 liters

aleksklad [387]

Answer:

650 milliliters.

Step-by-step explanation:

Amount in the Jug = 1.5 * 1000 = 1,500 mls.

She pours out 250 mls and 0.6 * 1000 = 600 mls

The amount left = 1500 - 250 - 600

= 650 milliliters.

7 0

3 years ago