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zhannawk [14.2K]

3 years ago

8

Suppose you earn 7.25 per hour working part time for a florist. Write and solve an inequality to find how many full hours you mu

st work to earn at least 125$

2 answers:

Mnenie [13.5K]3 years ago

7 0

17-18 !!!!!!!!!!!!!!!!

tiny-mole [99]3 years ago

5 0

17-18 hours i hope i helped

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A ticke cost 40 dollars suppose every seat in the first ten rolls are filled what is the total revenue from those seatss

KonstantinChe [14]

If a single ticket costs 40 dollars then the ten seats will generate the following

$40 x 10= $400

7 0

2 years ago

HELP HOW DO YOU WORK THIS OUT!!

Harrizon [31]

Answer:

I believe it would be 4/6

Step-by-step explanation:

You have four different ways to get a sum of 7: 1 and 6; 2 and 5; 3 and 4; or 4 and 3.

4 0

3 years ago

Which of the following equations have complex roots?

mestny [16]

Answer:

A

Step-by-step explanation:

Complex roots of quadratic functions occur when the <u>discriminant is negative</u>.

<u>Discriminant</u>

$b^2-4ac\quad\textsf{when}\:\:ax^2+bx+c=0$

Evaluate the discriminant of each of the given equations.

$\textsf{A.} \quad 3x^2+2=0$

$\implies a=3, \quad b=0, \quad c=2$

$\implies b^2-4ac=0^2-4(3)(2)=-24$

As -24 < 0 the equation will have complex roots.

$\textsf{B.} \quad 2x^2+1=7x$

$\implies 2x^2-7x+1=0$

$\implies a=2, \quad b=-7, \quad c=1$

$\implies b^2-4ac= (-7)^2-4(2)(1)=41$

As 41 > 0 the equation does not have complex roots.

$\textsf{C.} \quad 3x^2-1=6x$

$\implies 3x^2-6x-1=0$

$\implies a=3, \quad b=-6, \quad c=-1$

$\implies b^2-4ac=(-6)^2-4(3)(-1)=48$

As 48 > 0 the equation does not have complex roots.

$\textsf{D.} \quad 2x^2-1=5x$

$\implies 2x^2-5x-1=0$

$\implies a=2, \quad b=-5, \quad c=-1$

$\implies b^2-4ac=(-5)^2-4(2)(-1)=33$

As 33 > 0 the equation does not have complex roots.

Learn more about discriminants here:

brainly.com/question/27444516

brainly.com/question/27869538

Learn more about complex roots here:

brainly.com/question/26344541

6 0

2 years ago

Express x^2y^2+x^2+y^2+1

Hitman42 [59]

Answer:

( y^2 +1) ( x^2+1)

Step-by-step explanation:

Step 1 ) Factor out x^2 from the expression

x^2 (y^2+1)+y^2+1

Step 2) Factor out y^2 from the expression

(y^2+1) (x^2+1)

Solution is ( y^2 +1) ( x^2+1)

5 0

2 years ago

Write a real-world problem that can be represented by the equation 1/2x+6=20. Then solve the problem

butalik [34]

One-half of a number plus six will equal 20.

Solving:
1/2x + 6 = 20
-6 -6
1/2x = 14
*2/1 *2/1
x = 28 <--Answer to problem

8 0

2 years ago