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lesantik [10]
3 years ago
9

Solve the system using elimination. -9x - 4y = 1 3x + 3y = 3 ([?], [])

Mathematics
1 answer:
irakobra [83]3 years ago
7 0

Step-by-step explanation:

-9x-4y=1....eq1

3x+3y=3.....eq2

multiply eq2 by 3

to get

9x+9y=9....eq3

add eq1 and 3

0+5y=10

5y=10

divide both sides by 5

y=2

substitute y=2 in to eq1

-9x-4(2)=1

-9x-8=1

grouping of like terms

-9x=1+8

-9x=9

divide both sides by -9

x= -1

now the answer is

x= -1, y=2

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bearhunter [10]
Form an equation. Start by representing the number you want to find as X. Now add 1.
X + 1
Now we need to triple it. That basically means multiply X+1 by 3. You can write that as:
3 (X + 1)
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3 (X + 1) =
And now write X + 17
3 (X + 1) = X + 17

Now we solve for X.
Firstly, let's get rid of the X on the right.
Remember, if we want to get rid of a number of variable on one side, we need to use opposites, and do the same to the other side of the equation.
In this case, we have a positive X on the right. To get rid of that, we subtract X from both sides. This will leave us with:
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Now let's get rid of the +3 on the left. To do this, we subtract 3 from both sides of the equation.
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Now we just need to get X by itself. The 2 in front of the X multiplies X by 2. Therefore, to get X on its own, we need to divide 2x by 2, which just gives us 2.
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3 years ago
The school uses between 300 and 400 sheets of paper per school day. If paper costs the school $2.00 per 100 sheets, approximatel
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Answer:

  • Option A. $140.00

Explanation:

<u>1. Using the minimun number of sheets  of paper in the interval [300, 400]</u>

a) Cost: $ 2.00 / 100 sheets

b) 300 sheets / day × $ 2.00 / 100 sheets = $ 6.00 / day

c) Approimately 20 school days per month:

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<u>2. Using the maximum number of sheets of paper in the interval [300, 400]</u>

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<u>3. Middle value:</u>

Calculate the middle value between $160.00 and $120.00

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Thus, the answer is the option A.

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